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C=40(5-s) After Hiro's family photoshoot, the photographer sells the printed photos by the sheet. Hiro has a $200 credit from a prior session, and the equation gives the total credit left, C, in dollars, if he buys s sheets. How many sheets can Hiro purchase with his credit? Choose 1 answer: A 5 sheets (B) 8 sheets (C) 40 sheets (D) 200 sheets

C=40(5−s) C=40(5-s) \newlineAfter Hiro's family photoshoot, the photographer sells the printed photos by the sheet. Hiro has a $200 \$ 200 credit from a prior session, and the equation gives the total credit left, C C , in dollars, if he buys s s sheets. How many sheets can Hiro purchase with his credit?\newlineChoose 11 answer:\newline(A) 55 sheets\newline(B) 88 sheets\newline(C) 4040 sheets\newline(D) 200200 sheets

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Q. C=40(5−s) C=40(5-s) \newlineAfter Hiro's family photoshoot, the photographer sells the printed photos by the sheet. Hiro has a $200 \$ 200 credit from a prior session, and the equation gives the total credit left, C C , in dollars, if he buys s s sheets. How many sheets can Hiro purchase with his credit?\newlineChoose 11 answer:\newline(A) 55 sheets\newline(B) 88 sheets\newline(C) 4040 sheets\newline(D) 200200 sheets
  1. Understand the equation: Understand the equation and what it represents.\newlineThe equation C=40(5−s)C = 40(5 - s) represents the total credit left, CC, in dollars, after Hiro buys ss sheets. Hiro has a $200\$200 credit to start with.
  2. Set up the equation: Set up the equation to solve for the number of sheets Hiro can purchase with his $200\$200 credit.\newlineWe know that Hiro's total credit after purchasing sheets is $200\$200, so we set CC to 200200 and solve for ss:\newline200=40(5−s)200 = 40(5 - s)
  3. Distribute the 4040: Distribute the 4040 into the parentheses. \newline200=40×5−40×s200 = 40 \times 5 - 40 \times s\newline200=200−40s200 = 200 - 40s
  4. Isolate the variable: Isolate the variable ss on one side of the equation.\newlineTo do this, we can subtract 200200 from both sides of the equation:\newline200−200=200−200−40s200 - 200 = 200 - 200 - 40s\newline0=−40s0 = -40s

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