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Anna has a 25 -meter-long fence that she plans to use to enclose a rectangular garden of width 
w. The fencing will be placed around all four sides of the garden so that its area is 25 square meters.
Write an equation in terms of 
w that models the situation.

Anna has a 2525 -meter-long fence that she plans to use to enclose a rectangular garden of width w w . The fencing will be placed around all four sides of the garden so that its area is 2525 square meters.\newlineWrite an equation in terms of w w that models the situation.

Full solution

Q. Anna has a 2525 -meter-long fence that she plans to use to enclose a rectangular garden of width w w . The fencing will be placed around all four sides of the garden so that its area is 2525 square meters.\newlineWrite an equation in terms of w w that models the situation.
  1. Perimeter of the garden: Let's denote the width of the garden as ww meters and the length as ll meters. The perimeter of the rectangle is the sum of all its sides, which is given by the formula P=2l+2wP = 2l + 2w. Since Anna has a 2525-meter-long fence, the perimeter of the garden is 2525 meters. So we have:\newlineP=2l+2w=25P = 2l + 2w = 25
  2. Area of the garden: We also know that the area of the rectangle is given by the formula A=l×wA = l \times w. Anna wants the area of the garden to be 2525 square meters, so we have:\newlineA=l×w=25A = l \times w = 25
  3. Solving for l: Now we have two equations:\newline11) 2l+2w=252l + 2w = 25 (perimeter)\newline22) l×w=25l \times w = 25 (area)\newlineWe can solve one of the equations for ll and then substitute it into the other equation. Let's solve the perimeter equation for ll:\newline2l=252w2l = 25 - 2w\newlinel=252w2l = \frac{25 - 2w}{2}
  4. Substituting l l into the area equation: Substitute the expression for l l from the perimeter equation into the area equation:\newlinelw=25 l \cdot w = 25 \newline(252w2)w=25 \left(\frac{25 - 2w}{2}\right) \cdot w = 25
  5. Simplifying the equation: Now, we simplify the equation:\newline(25w2w2)/2=25(25w - 2w^2) / 2 = 25\newlineMultiply both sides by 22 to get rid of the fraction:\newline25w2w2=5025w - 2w^2 = 50
  6. Rearranging the equation: Rearrange the equation to set it to zero:\newline2w2+25w50=0-2w^2 + 25w - 50 = 0
  7. Correcting the error: This is a quadratic equation in terms of ww. However, we made a mistake in the previous step. The correct equation should be:\newline2w225w+50=02w^2 - 25w + 50 = 0\newlineWe need to correct this error.

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