Anna has a 25 -meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed around all four sides of the garden so that its area is 25 square meters.Write an equation in terms of w that models the situation.
Q. Anna has a 25 -meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed around all four sides of the garden so that its area is 25 square meters.Write an equation in terms of w that models the situation.
Perimeter of the garden: Let's denote the width of the garden as w meters and the length as l meters. The perimeter of the rectangle is the sum of all its sides, which is given by the formula P=2l+2w. Since Anna has a 25-meter-long fence, the perimeter of the garden is 25 meters. So we have:P=2l+2w=25
Area of the garden: We also know that the area of the rectangle is given by the formula A=l×w. Anna wants the area of the garden to be 25 square meters, so we have:A=l×w=25
Solving for l: Now we have two equations:1) 2l+2w=25 (perimeter)2) l×w=25 (area)We can solve one of the equations for l and then substitute it into the other equation. Let's solve the perimeter equation for l:2l=25−2wl=225−2w
Substituting l into the area equation: Substitute the expression for l from the perimeter equation into the area equation:l⋅w=25(225−2w)⋅w=25
Simplifying the equation: Now, we simplify the equation:(25w−2w2)/2=25Multiply both sides by 2 to get rid of the fraction:25w−2w2=50
Rearranging the equation: Rearrange the equation to set it to zero:−2w2+25w−50=0
Correcting the error: This is a quadratic equation in terms of w. However, we made a mistake in the previous step. The correct equation should be:2w2−25w+50=0We need to correct this error.
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