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An architect has created a scale drawing for a residential townhouse in the shape of a rectangular prism. In the drawing, the internal width of the townhouse is labeled as 18 feet 
(ft), the internal length as 
20ft, and the internal height as 
30ft. The local building department tells the architect that if built, the building would be too tall according to local zoning laws and that its height must be reduced by 
10%. If the architect creates a second scale drawing where the townhouse's height is reduced by 
10%, what will be its new proposed internal volume in cubic feet?

An architect has created a scale drawing for a residential townhouse in the shape of a rectangular prism. In the drawing, the internal width of the townhouse is labeled as 1818 feet (ft) (\mathrm{ft}) , the internal length as 20ft 20 \mathrm{ft} , and the internal height as 30ft 30 \mathrm{ft} . The local building department tells the architect that if built, the building would be too tall according to local zoning laws and that its height must be reduced by 10% 10 \% . If the architect creates a second scale drawing where the townhouse's height is reduced by 10% 10 \% , what will be its new proposed internal volume in cubic feet?

Full solution

Q. An architect has created a scale drawing for a residential townhouse in the shape of a rectangular prism. In the drawing, the internal width of the townhouse is labeled as 1818 feet (ft) (\mathrm{ft}) , the internal length as 20ft 20 \mathrm{ft} , and the internal height as 30ft 30 \mathrm{ft} . The local building department tells the architect that if built, the building would be too tall according to local zoning laws and that its height must be reduced by 10% 10 \% . If the architect creates a second scale drawing where the townhouse's height is reduced by 10% 10 \% , what will be its new proposed internal volume in cubic feet?
  1. Calculate original volume: Calculate the original volume of the townhouse.\newlineThe formula for the volume of a rectangular prism is length×width×height\text{length} \times \text{width} \times \text{height}.\newlineOriginal volume = 20ft20 \, \text{ft} (length) ×18ft\times 18 \, \text{ft} (width) ×30ft\times 30 \, \text{ft} (height).
  2. Perform calculation for original volume: Perform the calculation for the original volume.\newlineOriginal volume = 20ft×18ft×30ft=10,800cubic feet.20 \, \text{ft} \times 18 \, \text{ft} \times 30 \, \text{ft} = 10,800 \, \text{cubic feet}.
  3. Calculate new height after reduction: Calculate the new height after reducing it by 10%10\%. \newline10%10\% of the original height is 10%×30 ft=0.10×30 ft=3 ft10\% \times 30 \text{ ft} = 0.10 \times 30 \text{ ft} = 3 \text{ ft}. \newlineNew height = original height - reduction = 30 ft3 ft=27 ft30 \text{ ft} - 3 \text{ ft} = 27 \text{ ft}.
  4. Calculate new volume with reduced height: Calculate the new volume with the reduced height.\newlineNew volume = length ×\times width ×\times new height.\newlineNew volume = 2020 ft ×\times 1818 ft ×\times 2727 ft.
  5. Perform calculation for new volume: Perform the calculation for the new volume.\newlineNew volume = 20ft×18ft×27ft=9,720cubic feet.20 \, \text{ft} \times 18 \, \text{ft} \times 27 \, \text{ft} = 9,720 \, \text{cubic feet}.

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