Amira had (3)/(4) of a bag of cat food. The food lasted 7(1)/(2) weeks. How much cat food did Amira's cats eat per week? bags

Identify total amount and duration: Identify the total amount of cat food Amira had and the duration it lasted. Amira had (3)/(4) of a bag of cat food, and it lasted 7(1)/(2) weeks.Convert to improper fraction: Convert the mixed number 7(1)/(2) weeks into an improper fraction to make the calculation easier. 7(1)/(2) weeks = (7 * 2 + 1) / 2 = (14 + 1) / 2 = 15/2 weeks.Calculate amount consumed per week: Calculate the amount of cat food consumed per week by dividing the total amount of cat food by the number of weeks it lasted. (3)/(4) bag of cat food ÷ (15)/(2) weeks = (3)/(4) * (2)/(15) = (3 * 2) / (4 * 15) = 6 / 60.Simplify fraction obtained: Simplify the fraction obtained in Step 3 to find the amount of cat food consumed per week. 6 / 60 can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 6. 6 / 60 = 1 / 10.

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Amira had
(3)/(4) of a bag of cat food.
The food lasted
7(1)/(2) weeks.
How much cat food did Amira's cats eat per week?
bags

Amira had $\frac{3}{4}$ of a bag of cat food. $\newline$ The food lasted $7 \frac{1}{2}$ weeks. $\newline$ How much cat food did Amira's cats eat per week? $\newline$ bags

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Grade 7

GCF and LCM: word problems

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Q. Amira had

\frac{3}{4}

of a bag of cat food.

\newline

The food lasted

7 \frac{1}{2}

weeks.

\newline

How much cat food did Amira's cats eat per week?

\newline

bags

Identify total amount and duration: Identify the total amount of cat food Amira had and the duration it lasted. $\newline$ Amira had $\frac{3}{4}$ of a bag of cat food, and it lasted $7\frac{1}{2}$ weeks.
Convert to improper fraction: Convert the mixed number $7\frac{1}{2}$ weeks into an improper fraction to make the calculation easier. $7\frac{1}{2}$ weeks = $\left(7 \times 2 + 1\right) / 2 = \left(14 + 1\right) / 2 = \frac{15}{2}$ weeks.
Calculate amount consumed per week: Calculate the amount of cat food consumed per week by dividing the total amount of cat food by the number of weeks it lasted. $\newline$ $(\frac{3}{4})$ bag of cat food $\div$ $(\frac{15}{2})$ weeks = $(\frac{3}{4}) \times (\frac{2}{15})$ = $(\frac{3 \times 2}{4 \times 15})$ = $\frac{6}{60}$ .
Simplify fraction obtained: Simplify the fraction obtained in Step $3$ to find the amount of cat food consumed per week. $\newline$ $\frac{6}{60}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is $6$ . $\newline$ $\frac{6}{60} = \frac{1}{10}$ .