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Aiden is a taxi driver.

M(n) models Aiden's fee (in dollars) for his 
n^("th ") drive on a certain day.
What does the statement 
M(8) < M(4) mean?
Choose 1 answer:
(A) Aiden earned less money for his 
8^("th ") than he earned for his 
4^("th ") drive.
(B) Aiden earned 
$8 for a drive that was earlier than a drive for which he earned 
$4.
(c) Aiden earned 
$8 for fewer drives than the number of drives for which he earned 
$4.

Aiden is a taxi driver.\newlineM(n) M(n) models Aiden's fee (in dollars) for his nth  n^{\text {th }} drive on a certain day.\newlineWhat does the statement \( M(8)

Full solution

Q. Aiden is a taxi driver.\newlineM(n) M(n) models Aiden's fee (in dollars) for his nth  n^{\text {th }} drive on a certain day.\newlineWhat does the statement M(8)<M(4) M(8)<M(4) mean?\newlineChoose 11 answer:\newline(A) Aiden earned less money for his 8th  8^{\text {th }} than he earned for his 4th  4^{\text {th }} drive.\newline(B) Aiden earned $8 \$ 8 for a drive that was earlier than a drive for which he earned $4 \$ 4 .\newline(C) Aiden earned $8 \$ 8 for fewer drives than the number of drives for which he earned $4 \$ 4 .
  1. Function M(n)M(n): Understand the function M(n)M(n).M(n)M(n) is a function that models Aiden's fee for his nnth drive on a certain day. The variable nn represents the sequence number of the drive, and M(n)M(n) represents the fee earned for that particular drive.
  2. Interpretation of M(8) < M(4): Interpret M(8) < M(4).\newlineThe statement M(8) < M(4) means that the fee Aiden earned for his 8th8^{\text{th}} drive (M(8)M(8)) is less than the fee he earned for his 4th4^{\text{th}} drive (M(4)M(4)). This is a direct comparison of the fees earned on two different drives.
  3. Matching the interpretation to choices: Match the interpretation to the given choices.\newlineBased on the interpretation in Step 22, we can match the meaning of M(8) < M(4) to the given choices. It corresponds to choice (A), which states that Aiden earned less money for his 8th8^{\text{th}} drive than he earned for his 4th4^{\text{th}} drive.

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