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A reservoir can be filled to 
(1)/(4) capacity in 1 day by Pump A, and to 
(1)/(3) capacity in 1 day by Pump B.
Both pumps have a constant rate of flow. Which of the following inequalities best describes the number of days, 
d, it will take for both pumps working at the same time to fill the reservoir to over 
(7)/(8) capacity?
Choose 1 answer:
(A) 
(12)/(7)d > (7)/(8)
(B) 
(4)/(d)+(3)/(d) <= (7)/(8)
(C) 
(7)/(12)d > (7)/(8)
(D) 
(d)/(4)+(d)/(3) <= (7)/(8)
ar equations word problems | Lesson

A reservoir can be filled to 14 \frac{1}{4} capacity in 11 day by Pump A, and to 13 \frac{1}{3} capacity in 11 day by Pump B. Both pumps have a constant rate of flow. Which of the following inequalities best describes the number of days, d d , it will take for both pumps working at the same time to fill the reservoir to over 78 \frac{7}{8} capacity?\newlineChoose 11 answer:\newline(A) \frac{12}{7} d>\frac{7}{8} \newline(B) 4d+3d78 \frac{4}{d}+\frac{3}{d} \leq \frac{7}{8} \newline(C) \frac{7}{12} d>\frac{7}{8} \newline(D) d4+d378 \frac{d}{4}+\frac{d}{3} \leq \frac{7}{8} \newlinear equations word problems | Lesson

Full solution

Q. A reservoir can be filled to 14 \frac{1}{4} capacity in 11 day by Pump A, and to 13 \frac{1}{3} capacity in 11 day by Pump B. Both pumps have a constant rate of flow. Which of the following inequalities best describes the number of days, d d , it will take for both pumps working at the same time to fill the reservoir to over 78 \frac{7}{8} capacity?\newlineChoose 11 answer:\newline(A) 127d>78 \frac{12}{7} d>\frac{7}{8} \newline(B) 4d+3d78 \frac{4}{d}+\frac{3}{d} \leq \frac{7}{8} \newline(C) 712d>78 \frac{7}{12} d>\frac{7}{8} \newline(D) d4+d378 \frac{d}{4}+\frac{d}{3} \leq \frac{7}{8} \newlinear equations word problems | Lesson
  1. Calculate Combined Rate: Let's determine the combined rate of both pumps working together. Pump A fills (1)/(4)(1)/(4) of the reservoir in 11 day, and Pump B fills (1)/(3)(1)/(3) of the reservoir in 11 day. To find the combined rate, we add these fractions together.\newlineCombined rate = (1)/(4)+(1)/(3)(1)/(4) + (1)/(3)\newlineTo add fractions, we need a common denominator, which is 1212 in this case.\newlineCombined rate = (3)/(12)+(4)/(12)(3)/(12) + (4)/(12)\newlineCombined rate = (7)/(12)(7)/(12)\newlineThis means that together, the pumps can fill (7)/(12)(7)/(12) of the reservoir in 11 day.
  2. Set Up Inequality: Now, let's set up an inequality to find the number of days, dd, it takes to fill more than 78\frac{7}{8} of the reservoir's capacity.\newline\frac{7}{12}d > \frac{7}{8}\newlineWe want to solve for dd.
  3. Isolate Variable: To solve the inequality, we need to isolate dd. We can do this by multiplying both sides of the inequality by the reciprocal of 712\frac{7}{12}, which is 127\frac{12}{7}. \newlined > \frac{7}{8} \times \frac{12}{7}
  4. Simplify Inequality: Now, we simplify the right side of the inequality by canceling out the 77s.\newlined > \frac{12}{8}\newlined > \frac{3}{2}\newlined > 1.5\newlineThis means it will take more than 1.51.5 days for both pumps to fill the reservoir to over 78\frac{7}{8} capacity.
  5. Match with Answer Choices: Looking at the answer choices, we need to find the one that matches our inequality. The correct inequality should represent that more than 1.51.5 days are needed to fill over 78\frac{7}{8} of the reservoir.\newline(A) \frac{12}{7}d > \frac{7}{8} - This is the inequality we derived, but it's not simplified.\newline(B) 4d+3d78\frac{4}{d}+\frac{3}{d} \leq \frac{7}{8} - This is incorrect because it suggests the sum of the reciprocals of the days, which doesn't make sense in this context.\newline(C) \frac{7}{12}d > \frac{7}{8} - This is the inequality we started with, which is correct.\newline(D) d4+d378\frac{d}{4}+\frac{d}{3} \leq \frac{7}{8} - This is incorrect because it suggests the sum of the days divided by the rates, which is not the correct representation of the combined rate.

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