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A mug of warm apple cider is gradually cooling. Its temperature in degrees Celsius 
(^(@)C) can be modeled with the expression 
23+24*2^(-0.014 t), where the variable 
t represents the time in minutes. Approximately how many minutes will it take for the temperature to reach 
29^(@)C ?
(Round to the nearest minute.)

A mug of warm apple cider is gradually cooling. Its temperature in degrees Celsius (C) \left({ }^{\circ} \mathrm{C}\right) can be modeled with the expression 23+2420.014t 23+24 \cdot 2^{-0.014 t} , where the variable t t represents the time in minutes. Approximately how many minutes will it take for the temperature to reach 29C 29^{\circ} \mathrm{C} ?\newline(Round to the nearest minute.)

Full solution

Q. A mug of warm apple cider is gradually cooling. Its temperature in degrees Celsius (C) \left({ }^{\circ} \mathrm{C}\right) can be modeled with the expression 23+2420.014t 23+24 \cdot 2^{-0.014 t} , where the variable t t represents the time in minutes. Approximately how many minutes will it take for the temperature to reach 29C 29^{\circ} \mathrm{C} ?\newline(Round to the nearest minute.)
  1. Write temperature model and target: Write down the given temperature model and the target temperature.\newlineThe temperature model is given by the expression 23+24×20.014t23 + 24 \times 2^{-0.014t}, and we want to find the time tt when the temperature reaches 2929 degrees Celsius.
  2. Set model equal to target: Set the temperature model equal to the target temperature and solve for tt. \newline29=23+24×2(0.014t)29 = 23 + 24 \times 2^{(-0.014t)}
  3. Isolate exponential term: Subtract 2323 from both sides to isolate the exponential term.\newline2923=24×2(0.014t)29 - 23 = 24 \times 2^{(-0.014t)}\newline6=24×2(0.014t)6 = 24 \times 2^{(-0.014t)}
  4. Solve for exponential part: Divide both sides by 2424 to solve for the exponential part.\newline624=2(0.014t)\frac{6}{24} = 2^{(-0.014t)}\newline14=2(0.014t)\frac{1}{4} = 2^{(-0.014t)}
  5. Set exponents equal: Recognize that 14\frac{1}{4} is a power of 22, specifically 222^{-2}, and set the exponents equal to each other to solve for tt. \newline22=20.014t2^{-2} = 2^{-0.014t}\newline2=0.014t-2 = -0.014t
  6. Solve for t: Divide both sides by 0.014-0.014 to solve for tt.t=20.014t = \frac{-2}{-0.014}t142.857t \approx 142.857
  7. Round to nearest minute: Round the answer to the nearest minute.\newlinet143t \approx 143 minutes

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