A memory chip is being designed to hold a number of transistors and heat sinks. The transistors hold memory while the heat sinks cool the chip. There must be at least one heat sink for every 2,000 transistors to prevent overheating. Also, each transistor has an area of 2.0×10−10mm2 (square millimeters), each heat sink has an area of 3.6×10−6mm2, and the total area of transistors and heat sinks must be at most 2mm2. What is the approximate maximum number of transistors that the chip can hold according to this design?Choose 1 answer:(A) 2.78×102(B) 5.56×105(C) 1.0×109(D) 1.0×1010
Q. A memory chip is being designed to hold a number of transistors and heat sinks. The transistors hold memory while the heat sinks cool the chip. There must be at least one heat sink for every 2,000 transistors to prevent overheating. Also, each transistor has an area of 2.0×10−10mm2 (square millimeters), each heat sink has an area of 3.6×10−6mm2, and the total area of transistors and heat sinks must be at most 2mm2. What is the approximate maximum number of transistors that the chip can hold according to this design?Choose 1 answer:(A) 2.78×102(B) 5.56×105(C) 1.0×109(D) 1.0×1010
Determine Relationship: Determine the relationship between the number of transistors and heat sinks.According to the problem, there must be at least one heat sink for every 2,000 transistors. This means that for every heat sink, there can be up to 2,000 transistors.
Calculate Area: Calculate the area occupied by one heat sink and 2,000 transistors. The area of one heat sink is given as 3.6×10−6 mm2. The area of one transistor is given as 2.0×10−10 mm2. Therefore, the area for 2,000 transistors is 2,000×2.0×10−10 mm2=4.0×10−7 mm2.
Total Area Calculation: Calculate the total area for one heat sink and the corresponding 2,000 transistors.Total area for one set (one heat sink + 2,000 transistors) = Area of one heat sink + Area of 2,000 transistorsTotal area for one set = 3.6×10−6 mm2+4.0×10−7 mm2Total area for one set = 4.0×10−6 mm2
Maximum Sets Calculation: Determine the maximum number of sets that can fit within the total area constraint of 2 mm2. Total available area = 2 mm2 Area per set = 4.0×10−6 mm2 Maximum number of sets = Total available area / Area per set Maximum number of sets = 2 mm2/4.0×10−6 mm2 Maximum number of sets = 5.0×105
Calculate Maximum Transistors: Calculate the maximum number of transistors by multiplying the number of sets by the number of transistors per set.Maximum number of transistors = Maximum number of sets × Number of transistors per setMaximum number of transistors =5.0×105 sets ×2,000 transistors/setMaximum number of transistors =1.0×109 transistors
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