Identify Quadratic Equation: Identify the quadratic equation to solve: 9s^2 + 6s + 1 = 0.Use Quadratic Formula: Use the quadratic formula, s = [-b ± √(b^2 - 4ac)] / (2a), where a = 9, b = 6, and c = 1.Calculate Discriminant: Calculate the discriminant, Δ = b^2 - 4ac = (6)^2 - 4(9)(1) = 36 - 36 = 0.Find Real Root: Since the discriminant Δ = 0, there is one real root, s = -b / (2a).Substitute Values: Substitute a and b into the formula: s = -6 / (2*9) = -6 / 18 = -1/3.

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$9s^2 + 6s + 1 = 0$

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Grade 6

Add three or more integers

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9s^2 + 6s + 1 = 0

Identify Quadratic Equation: Identify the quadratic equation to solve: $9s^2 + 6s + 1 = 0$ .
Use Quadratic Formula: Use the quadratic formula, $s = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ , where $a = 9$ , $b = 6$ , and $c = 1$ .
Calculate Discriminant: Calculate the discriminant, $\Delta = b^2 - 4ac = (6)^2 - 4(9)(1) = 36 - 36 = 0$ .
Find Real Root: Since the discriminant $\Delta = 0$ , there is one real root, $s = -\frac{b}{2a}$ .
Substitute Values: Substitute $a$ and $b$ into the formula: $s = -6 / (2\cdot9) = -6 / 18 = -1/3$ .