Set up division problem: Step 1: Set up the division problem. Divide 933 by 32 to find how many times 32 fits into 933. Calculation: 933 ÷ 32Perform the division: Step 2: Perform the division. Using long division, 32 goes into 93 two times (because 32 x 3 = 96, which is too high). Subtract 64 (2 x 32) from 93 to get a remainder of 29. Bring down the next digit from 933, which is 3, making it 293.Continue the division: Step 3: Continue the division. 32 goes into 293 nine times (because 32 x 9 = 288). Subtract 288 from 293 to get a remainder of 5. Since there are no more digits to bring down, the division is complete.

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Divide: $933\div32$

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Q. Divide:

933\div32

Set up division problem: Step $1$ : Set up the division problem. $\newline$ Divide $933$ by $32$ to find how many times $32$ fits into $933$ . $\newline$ Calculation: $933 \div 32$
Perform the division: Step $2$ : Perform the division. $\newline$ Using long division, $32$ goes into $93$ two times (because $32 \times 3 = 96$ , which is too high). $\newline$ Subtract $64$ ( $2 \times 32$ ) from $93$ to get a remainder of $29$ . $\newline$ Bring down the next digit from $933$ , which is $3$ , making it $293$ .
Continue the division: Step $3$ : Continue the division. $\newline$ $32$ goes into $293$ nine times (because $32 \times 9 = 288$ ). $\newline$ Subtract $288$ from $293$ to get a remainder of $5$ . $\newline$ Since there are no more digits to bring down, the division is complete.