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Let’s check out your problem:
9
+
n
×
2
9 + n \times 2
9
+
n
×
2
for
n
=
3
n = 3
n
=
3
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Math Problems
Algebra 1
Factor polynomials
Full solution
Q.
9
+
n
×
2
9 + n \times 2
9
+
n
×
2
for
n
=
3
n = 3
n
=
3
Plug in value of
n
n
n
:
First, let's plug in the value of
n
n
n
into the expression.
\newline
So we have
9
+
3
×
2
9 + 3 \times 2
9
+
3
×
2
.
Perform multiplication:
Now, let's do the multiplication part first because of the order of operations (PEMDAS/BODMAS).
\newline
That's
3
×
2
3 \times 2
3
×
2
which is
6
6
6
.
Add the result to
9
9
9
:
Next, we add that result to
9
9
9
. So it's
9
+
6
9 + 6
9
+
6
.
Do the final addition:
Finally, we do the addition.
9
+
6
9 + 6
9
+
6
equals
15
15
15
.
More problems from Factor polynomials
Question
Find the greatest common factor.
\newline
9
v
3
,
6
v
3
9v^3, 6v^3
9
v
3
,
6
v
3
\newline
\newline
Write your answer as a constant times a product of single variables raised to exponents.
\newline
‾
\underline{\hspace{1cm}}
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Posted 9 months ago
Question
Factor out the greatest common factor. If the greatest common factor is
1
1
1
, just retype the polynomial.
\newline
6
x
3
+
9
x
2
6x^3 + 9x^2
6
x
3
+
9
x
2
\newline
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Posted 9 months ago
Question
Factor.
\newline
k
2
+
9
k
+
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k^2 + 9k + 18
k
2
+
9
k
+
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\newline
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Posted 9 months ago
Question
Factor.
\newline
9
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−
16
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−
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\newline
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Question
Factor.
\newline
j
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+
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+
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+
10
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j
3
+
2
j
2
+
5
j
+
10
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Posted 9 months ago
Question
Factor
x
4
+
6
x
2
+
9
x^4 + 6x^2 + 9
x
4
+
6
x
2
+
9
completely.
\newline
All factors in your answer should have integer coefficients.
\newline
______
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Posted 1 year ago
Question
Factor.
\newline
z
2
+
13
z
+
22
z^2 + 13z + 22
z
2
+
13
z
+
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\newline
______
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Posted 1 year ago
Question
Simplify the expression:
\newline
5
x
+
9
x
−
4
x
−
2
x
5x + 9x - 4x - 2x
5
x
+
9
x
−
4
x
−
2
x
\newline
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Posted 1 year ago
Question
3
−
3
2
3 - 3^2
3
−
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5
−
5
2
5 - 5^2
5
−
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