Simplify the expression. 9-3÷(1)/(3)+1=?

Addressing division and parentheses: According to the order of operations (PEMDAS/BODMAS), we first need to address the division and parentheses. The expression inside the parentheses is (1/3), which is already simplified. So we will perform the division next: 3 ÷ (1/3).Performing the division: Dividing by a fraction is the same as multiplying by its reciprocal. Therefore, 3 ÷ (1/3) is the same as 3 × 3, which equals 9.Substituting the result: Now we substitute the result of the division back into the original expression, which gives us 9 - 9 + 1.Performing the subtraction: Next, we perform the subtraction: 9 - 9 equals 0.Adding the remaining number: Finally, we add the remaining number to the result of the subtraction: 0 + 1 equals 1.

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Simplify the expression. $\newline$ $9-3÷\frac{1}{3}+1=?$

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Grade 6

Add three or more integers

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Q. Simplify the expression.

\newline

9-3÷\frac{1}{3}+1=?

Addressing division and parentheses: According to the order of operations (PEMDAS/BODMAS), we first need to address the division and parentheses. The expression inside the parentheses is $(\frac{1}{3})$ , which is already simplified. So we will perform the division next: $3 \div (\frac{1}{3})$ .
Performing the division: Dividing by a fraction is the same as multiplying by its reciprocal. Therefore, $3 \div \left(\frac{1}{3}\right)$ is the same as $3 \times 3$ , which equals $9$ .
Substituting the result: Now we substitute the result of the division back into the original expression, which gives us $9 - 9 + 1$ .
Performing the subtraction: Next, we perform the subtraction: $9 - 9$ equals $0$ .
Adding the remaining number: Finally, we add the remaining number to the result of the subtraction: $0 + 1$ equals $1$ .