Q. 8y=4x2−12x+46y=23x+45If (a,b) is the solution to the system of equations shown, what is the value of a ?
Substitute y into first equation: We have a system of two equations:1) 8y=4x2−12x+462) y=23x+45To find the solution to the system, we need to substitute the second equation into the first one to solve for x.
Distribute 8 on left side: Substitute y from the second equation into the first equation:8(23x+45)=4x2−12x+46
Rearrange equation and solve: Distribute 8 on the left side of the equation:8×(23)x+8×(45)=4x2−12x+4612x+10=4x2−12x+46
Divide and simplify: Rearrange the equation to set it to zero and solve for x:4x2−12x−12x−10+46=04x2−24x+36=0
Factor the quadratic equation: Divide the entire equation by 4 to simplify:x2−6x+9=0
Set factors equal to zero: Factor the quadratic equation: (x - \(3)(x - 3) = 0
Find x value: Set each factor equal to zero and solve for x:x−3=0x=3
Final solution for a: We found the value of x to be 3. Since we are looking for the value of a, and (a,b) is the solution to the system, a=x.
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