Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

8log_(5)a+2log_(5)b

22) 8log5a+2log5b 8 \log _{5} a+2 \log _{5} b

Full solution

Q. 22) 8log5a+2log5b 8 \log _{5} a+2 \log _{5} b
  1. Rewrite using power rule: We are given the expression 8log5(a)+2log5(b)8\log_5(a) + 2\log_5(b) and we need to simplify it. According to the properties of logarithms, specifically the power rule which states that mloga(b)=loga(bm)m\log_a(b) = \log_a(b^m), we can rewrite each term by moving the coefficients as exponents inside the logarithms.
  2. Apply power rule to first term: Applying the power rule to the first term, we get log5(a8)\log_5(a^8).
  3. Apply power rule to second term: Applying the power rule to the second term, we get log5(b2)\log_5(b^2).
  4. Combine using product rule: Now we have the expression log5(a8)+log5(b2)\log_5(a^8) + \log_5(b^2). According to the properties of logarithms, specifically the product rule which states that loga(x)+loga(y)=loga(xy)\log_a(x) + \log_a(y) = \log_a(xy), we can combine these two logarithms into a single logarithm.
  5. Final simplified expression: Combining the two logarithms using the product rule gives us log5(a8b2)\log_5(a^8 \cdot b^2).
  6. Final simplified expression: Combining the two logarithms using the product rule gives us log5(a8b2)\log_5(a^8 \cdot b^2).The expression log5(a8b2)\log_5(a^8 \cdot b^2) is the simplified form of the original expression 8log5(a)+2log5(b)8\log_5(a) + 2\log_5(b).

More problems from Domain and range of square root functions: equations