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7,900 dollars is placed in a savings account with an annual interest rate of 
3%. If no money is added or removed from the account, which equation represents how much will be in the account after 5 years?

M=7,900(1.3)^(5)

M=7,900(1-0.03)^(5)

M=7,900(0.97)^(5)

M=7,900(1.03)^(5)

77,900900 dollars is placed in a savings account with an annual interest rate of 3% 3 \% . If no money is added or removed from the account, which equation represents how much will be in the account after 55 years?\newlineM=7,900(1.3)5 M=7,900(1.3)^{5} \newlineM=7,900(10.03)5 M=7,900(1-0.03)^{5} \newlineM=7,900(0.97)5 M=7,900(0.97)^{5} \newlineM=7,900(1.03)5 M=7,900(1.03)^{5}

Full solution

Q. 77,900900 dollars is placed in a savings account with an annual interest rate of 3% 3 \% . If no money is added or removed from the account, which equation represents how much will be in the account after 55 years?\newlineM=7,900(1.3)5 M=7,900(1.3)^{5} \newlineM=7,900(10.03)5 M=7,900(1-0.03)^{5} \newlineM=7,900(0.97)5 M=7,900(0.97)^{5} \newlineM=7,900(1.03)5 M=7,900(1.03)^{5}
  1. Compound Interest Formula: To find the amount in the savings account after 55 years with compound interest, we use the formula for compound interest: A=P(1+r/n)(nt)A = P(1 + r/n)^{(nt)}, where AA is the amount of money accumulated after nn years, including interest, PP is the principal amount (the initial amount of money), rr is the annual interest rate (decimal), nn is the number of times that interest is compounded per year, and tt is the time the money is invested for in years. Since the problem does not specify the compounding frequency, we assume it is compounded once per year (n=1n=1). Therefore, the formula simplifies to A=P(1+r)tA = P(1 + r)^t.
  2. Given Values: We are given:\newlineP=$7,900P = \$7,900 (the initial deposit),\newliner=3%r = 3\% annual interest rate, which as a decimal is 0.030.03,\newlinet=5t = 5 years.\newlineWe need to plug these values into the simplified compound interest formula A=P(1+r)tA = P(1 + r)^t.
  3. Substitute Values: Substituting the given values into the formula, we get:\newlineA=7,900(1+0.03)5A = 7,900(1 + 0.03)^5\newlineThis simplifies to:\newlineA=7,900(1.03)5A = 7,900(1.03)^5\newlineThis is the correct representation of the amount in the account after 55 years.

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