Q. Find factors of the quadratic expression: 6x2−3x−9(?x+?)(x+?)
Identify Factors: We need to factor the quadratic expression 6x2−3x−9. To do this, we look for two numbers that multiply to give the product of the coefficient of x2 (which is 6) and the constant term (which is −9), and add up to the coefficient of x (which is −3).
Calculate Product: The product of the coefficient of x2 and the constant term is 6×−9=−54. We need to find two numbers that multiply to −54 and add up to −3.
Find Suitable Numbers: The two numbers that satisfy these conditions are −9 and 6, because −9×6=−54 and −9+6=−3.
Perform Decomposition: Now we rewrite the middle term of the quadratic expression using the two numbers we found. This is known as decomposition. 6x2−3x−9 becomes 6x2−9x+6x−9.
Factor by Grouping: Next, we factor by grouping. We group the terms as follows: 6x2−9x + 6x−9.
Factor out Common Factor: We factor out the common factor from each group. From the first group, we can factor out 3x, and from the second group, we can factor out 3. This gives us: 3x(2x−3)+3(2x−3).
Factor out Common Factor: We notice that (2x−3) is a common factor in both terms, so we can factor it out.The expression becomes (2x−3)(3x+3).
Simplify Second Term: We can simplify the second term (3x+3) by factoring out the common factor of 3, which gives us 3(x+1).So the final factored form of the expression is (2x−3)(3)(x+1).
Write Final Answer: Since we are looking for factors in the form of ax+b)(cx+d)\, we can write the final answer as \(\(2x - 3)(3x + 3)\.
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