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Find factors of the quadratic expression: 6x23x96x^{2}-3x-9\newline(?x+?)(x+?)(?x+?)(x+?)

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Q. Find factors of the quadratic expression: 6x23x96x^{2}-3x-9\newline(?x+?)(x+?)(?x+?)(x+?)
  1. Identify Factors: We need to factor the quadratic expression 6x23x96x^2 - 3x - 9. To do this, we look for two numbers that multiply to give the product of the coefficient of x2x^2 (which is 66) and the constant term (which is 9-9), and add up to the coefficient of xx (which is 3-3).
  2. Calculate Product: The product of the coefficient of x2x^2 and the constant term is 6×9=546 \times -9 = -54. We need to find two numbers that multiply to 54-54 and add up to 3-3.
  3. Find Suitable Numbers: The two numbers that satisfy these conditions are 9-9 and 66, because 9×6=54-9 \times 6 = -54 and 9+6=3-9 + 6 = -3.
  4. Perform Decomposition: Now we rewrite the middle term of the quadratic expression using the two numbers we found. This is known as decomposition. \newline6x23x96x^2 - 3x - 9 becomes 6x29x+6x96x^2 - 9x + 6x - 9.
  5. Factor by Grouping: Next, we factor by grouping. We group the terms as follows: 6x29x6x^2 - 9x + 6x96x - 9.
  6. Factor out Common Factor: We factor out the common factor from each group. From the first group, we can factor out 3x3x, and from the second group, we can factor out 33. This gives us: 3x(2x3)+3(2x3)3x(2x - 3) + 3(2x - 3).
  7. Factor out Common Factor: We notice that (2x3)(2x - 3) is a common factor in both terms, so we can factor it out.\newlineThe expression becomes (2x3)(3x+3)(2x - 3)(3x + 3).
  8. Simplify Second Term: We can simplify the second term (3x+3)(3x + 3) by factoring out the common factor of 33, which gives us 3(x+1)3(x + 1).\newlineSo the final factored form of the expression is (2x3)(3)(x+1)(2x - 3)(3)(x + 1).
  9. Write Final Answer: Since we are looking for factors in the form of ax+b)(cx+d)\, we can write the final answer as \(\(2x - 33)(33x + 33)\.

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