5+4m^(2)+7m-m^(2)+3m-13 Which of the following is equivalent to the given expression? Choose 1 answer: (A) (3m-4)(m+2) (B) (3m+4)(m-2) (c) (3m-2)(m+4) (D) (3m+2)(m-4)

Combine Like Terms: Combine like terms in the expression 5+4m^2+7m-m^2+3m-13. We combine the m^2 terms: 4m^2 - m^2 = 3m^2. We combine the m terms: 7m + 3m = 10m. We combine the constant terms: 5 - 13 = -8. The simplified expression is 3m^2 + 10m - 8.Factor Quadratic Expression: Factor the quadratic expression 3m^2 + 10m - 8. We look for two numbers that multiply to (3)(-8) = -24 and add to 10. The numbers 12 and -2 satisfy these conditions because 12 * -2 = -24 and 12 + (-2) = 10. We rewrite the middle term using these numbers: 3m^2 + 12m - 2m - 8.Group and Factor: Group the terms to factor by grouping: (3m^2 + 12m) - (2m + 8). Factor out the common factor from each group: 3m(m + 4) - 2(m + 4).Factor Common Binomial: Factor out the common binomial factor (m + 4): (3m - 2)(m + 4). This is the factored form of the expression.

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5+4m^(2)+7m-m^(2)+3m-13
Which of the following is equivalent to the given expression?
Choose 1 answer:
(A)
(3m-4)(m+2)
(B)
(3m+4)(m-2)
(c)
(3m-2)(m+4)
(D)
(3m+2)(m-4)

$5+4 m^{2}+7 m-m^{2}+3 m-19$ $\newline$ Which of the following is equivalent to the given expression? $\newline$ Choose $1$ answer: $\newline$ (A) $(3 m-4)(m+2)$ $\newline$ (B) $(3 m+4)(m-2)$ $\newline$ (C) $(3 m-2)(m+4)$ $\newline$ (D) $(3 m+2)(m-4)$

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5+4 m^{2}+7 m-m^{2}+3 m-19

\newline

Which of the following is equivalent to the given expression?

\newline

Choose

1

answer:

\newline

(A)

(3 m-4)(m+2)

\newline

(B)

(3 m+4)(m-2)

\newline

(C)

(3 m-2)(m+4)

\newline

(D)

(3 m+2)(m-4)

Combine Like Terms: Combine like terms in the expression $5+4m^2+7m-m^2+3m-13$ . We combine the $m^2$ terms: $4m^2 - m^2 = 3m^2$ . We combine the $m$ terms: $7m + 3m = 10m$ . We combine the constant terms: $5 - 13 = -8$ . The simplified expression is $3m^2 + 10m - 8$ .
Factor Quadratic Expression: Factor the quadratic expression $3m^2 + 10m - 8$ . We look for two numbers that multiply to $(3)(-8) = -24$ and add to $10$ . The numbers $12$ and $-2$ satisfy these conditions because $12 \times -2 = -24$ and $12 + (-2) = 10$ . We rewrite the middle term using these numbers: $3m^2 + 12m - 2m - 8$ .
Group and Factor: Group the terms to factor by grouping: $(3m^2 + 12m) - (2m + 8)$ . Factor out the common factor from each group: $3m(m + 4) - 2(m + 4)$ .
Factor Common Binomial: Factor out the common binomial factor $(m + 4)$ : $(3m - 2)(m + 4)$ . $\newline$ This is the factored form of the expression.