4x−6−2y=4y+8x+22x+3=11Consider the given system of equations. If (x,y) is the solution to the system, then what is the value of x+y ?Choose 1 answer:(A) −8(B) 0(C) 8D There are no solutions to this system of equations.
Q. 4x−6−2y=4y+8x+22x+3=11Consider the given system of equations. If (x,y) is the solution to the system, then what is the value of x+y ?Choose 1 answer:(A) −8(B) 0(C) 8D There are no solutions to this system of equations.
Solve for x: First, let's solve the second equation for x.The equation is 2x+3=11.Subtract 3 from both sides to isolate the term with x.2x+3−3=11−32x=8Now, divide both sides by 2 to solve for x.22x=28x=4
Substitute x into first equation: Next, we substitute the value of x into the first equation to solve for y. The first equation is 4x−6−2y=4y+8x+2. Substitute x=4 into the equation. 4(4)−6−2y=4y+8(4)+216−6−2y=4y+32+2Simplify both sides. 10−2y=4y+34
Get y terms on one side: Now, let's get all the y terms on one side and the constants on the other side.Add 2y to both sides and subtract 34 from both sides.10−2y+2y−34=4y+2y+34−34Combine like terms.−24=6yNow, divide both sides by 6 to solve for y.6−24=66yy=−4
Find x+y: Finally, we find the value of x+y. We have x=4 and y=−4. x+y=4+(−4)x+y=0