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Solve the equation 4x3+4=04x^3 + 4 = 0

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Q. Solve the equation 4x3+4=04x^3 + 4 = 0
  1. Identify Equation Type: Identify the type of equation and isolate the variable term.\newlineThe given equation is a cubic equation in the form of ax3+c=0ax^3 + c = 0. We need to isolate the x3x^3 term to solve for xx.\newline4x3+4=04x^3 + 4 = 0\newlineSubtract 44 from both sides to isolate the x3x^3 term.\newline4x3=44x^3 = -4
  2. Isolate Variable Term: Divide both sides by the coefficient of x3x^3 to solve for x3x^3.\newlineDivide both sides by 44 to get x3x^3 on its own.\newlinex3=44x^3 = -\frac{4}{4}\newlinex3=1x^3 = -1
  3. Subtract Constant: Find the cube root of both sides to solve for xx. To find the value of xx, we take the cube root of both sides of the equation. x=(1)13x = (-1)^{\frac{1}{3}} Since the cube root of 1-1 is 1-1, we find that: x=1x = -1