3x^(2)+4xy^(2) Which of the following is equivalent to the given expression? Choose 1 answer: (A) x(3x+4y) (B) x(3x+4y^(2)) (c) x^(2)(3+4y) (D) x^(2)(3+4y^(2))

Identify Common Factors: To find an equivalent expression, we need to look for common factors in each term of the given expression 3x^(2)+4xy^(2).Factor Out Common Factor: The first term is 3x^(2), which has a factor of x. The second term is 4xy^(2), which also has a factor of x. Therefore, x is a common factor in both terms.Compare with Options: We can factor out the common x from both terms to get x(3x+4y^(2)).Now we compare the factored expression x(3x+4y^(2)) with the given options to find the equivalent expression.Option (A) is x(3x+4y), which is not equivalent because it does not have the y^(2) term in the second part of the expression.Option (B) is x(3x+4y^(2)), which is equivalent to our factored expression.Option (C) is x^(2)(3+4y), which is not equivalent because it suggests that both terms originally had an x^(2) factor, which is not the case.Option (D) is x^(2)(3+4y^(2)), which is also not equivalent because it suggests that both terms originally had an x^(2) factor, which is not the case.

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3x^(2)+4xy^(2)
Which of the following is equivalent to the given expression?
Choose 1 answer:
(A)
x(3x+4y)
(B)
x(3x+4y^(2))
(c)
x^(2)(3+4y)
(D)
x^(2)(3+4y^(2))

$3 x^{2}+4 x y^{2}$ $\newline$ Which of the following is equivalent to the given expression? $\newline$ Choose $1$ answer: $\newline$ (A) $x(3 x+4 y)$ $\newline$ (B) $x\left(3 x+4 y^{2}\right)$ $\newline$ (C) $x^{2}(3+4 y)$ $\newline$ (D) $x^{2}\left(3+4 y^{2}\right)$

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Math Problems

Algebra 1

Identify equivalent linear expressions

Full solution

3 x^{2}+4 x y^{2}

\newline

Which of the following is equivalent to the given expression?

\newline

Choose

1

answer:

\newline

(A)

x(3 x+4 y)

\newline

(B)

x\left(3 x+4 y^{2}\right)

\newline

(C)

x^{2}(3+4 y)

\newline

(D)

x^{2}\left(3+4 y^{2}\right)

Identify Common Factors: To find an equivalent expression, we need to look for common factors in each term of the given expression $3x^{2}+4xy^{2}$ .
Factor Out Common Factor: The first term is $3x^{2}$ , which has a factor of $x$ . The second term is $4xy^{2}$ , which also has a factor of $x$ . Therefore, $x$ is a common factor in both terms.
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .Now we compare the factored expression $x(3x+4y^{2})$ with the given options to find the equivalent expression.
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .Now we compare the factored expression $x(3x+4y^{2})$ with the given options to find the equivalent expression.Option (A) is $x(3x+4y)$ , which is not equivalent because it does not have the $y^{2}$ term in the second part of the expression.
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .Now we compare the factored expression $x(3x+4y^{2})$ with the given options to find the equivalent expression.Option (A) is $x(3x+4y)$ , which is not equivalent because it does not have the $y^{2}$ term in the second part of the expression.Option (B) is $x(3x+4y^{2})$ , which is equivalent to our factored expression.
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .Now we compare the factored expression $x(3x+4y^{2})$ with the given options to find the equivalent expression.Option (A) is $x(3x+4y)$ , which is not equivalent because it does not have the $y^{2}$ term in the second part of the expression.Option (B) is $x(3x+4y^{2})$ , which is equivalent to our factored expression.Option (C) is $x^{2}(3+4y)$ , which is not equivalent because it suggests that both terms originally had an $x^{2}$ factor, which is not the case.
Compare with Options: We can factor out the common $x$ from both terms to get $x(3x+4y^{2})$ .Now we compare the factored expression $x(3x+4y^{2})$ with the given options to find the equivalent expression.Option (A) is $x(3x+4y)$ , which is not equivalent because it does not have the $y^{2}$ term in the second part of the expression.Option (B) is $x(3x+4y^{2})$ , which is equivalent to our factored expression.Option (C) is $x^{2}(3+4y)$ , which is not equivalent because it suggests that both terms originally had an $x^{2}$ factor, which is not the case.Option (D) is $x^{2}(3+4y^{2})$ , which is also not equivalent because it suggests that both terms originally had an $x^{2}$ factor, which is not the case.