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Let’s check out your problem:
Evaluate
x
x
x
.
3
(
x
+
1
)
2
=
108
3(x+1)^2=108
3
(
x
+
1
)
2
=
108
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Math Problems
Grade 6
Add, subtract, multiply, or divide two fractions
Full solution
Q.
Evaluate
x
x
x
.
3
(
x
+
1
)
2
=
108
3(x+1)^2=108
3
(
x
+
1
)
2
=
108
Divide by
3
3
3
:
Divide both sides of the equation by
3
3
3
to simplify the equation.
\newline
3
(
x
+
1
)
2
3
=
108
3
\frac{3(x+1)^2}{3} = \frac{108}{3}
3
3
(
x
+
1
)
2
=
3
108
\newline
(
x
+
1
)
2
=
36
(x+1)^2 = 36
(
x
+
1
)
2
=
36
Take square root:
Take the
square root
of both sides to solve for
x
+
1
x+1
x
+
1
.
\newline
(
x
+
1
)
2
=
±
36
\sqrt{(x+1)^2} = \pm\sqrt{36}
(
x
+
1
)
2
=
±
36
\newline
x
+
1
=
±
6
x+1 = \pm6
x
+
1
=
±
6
Solve for positive root:
Solve for
x
x
x
by subtracting
1
1
1
from both sides of the equation for the positive root.
\newline
x
+
1
−
1
=
6
−
1
x + 1 - 1 = 6 - 1
x
+
1
−
1
=
6
−
1
\newline
x
=
5
x = 5
x
=
5
Solve for negative root:
Solve for
x
x
x
by subtracting
1
1
1
from both sides of the equation for the negative root.
x
+
1
−
1
=
−
6
−
1
x + 1 - 1 = -6 - 1
x
+
1
−
1
=
−
6
−
1
x
=
−
7
x = -7
x
=
−
7
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