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Evaluate xx. 3(x+1)2=1083(x+1)^2=108

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Q. Evaluate xx. 3(x+1)2=1083(x+1)^2=108
  1. Divide by 33: Divide both sides of the equation by 33 to simplify the equation.\newline3(x+1)23=1083\frac{3(x+1)^2}{3} = \frac{108}{3}\newline(x+1)2=36(x+1)^2 = 36
  2. Take square root: Take the square root of both sides to solve for x+1x+1.\newline(x+1)2=±36\sqrt{(x+1)^2} = \pm\sqrt{36}\newlinex+1=±6x+1 = \pm6
  3. Solve for positive root: Solve for xx by subtracting 11 from both sides of the equation for the positive root.\newlinex+11=61x + 1 - 1 = 6 - 1\newlinex=5x = 5
  4. Solve for negative root: Solve for xx by subtracting 11 from both sides of the equation for the negative root.x+11=61x + 1 - 1 = -6 - 1x=7x = -7

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