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3(TR)=103(T-R)=10, which of the following correctly expresses TT in terms of RR ? \newlineChoose 11 answer:\newline(A) T=(R+3)10T=\frac{(R+3)}{10}\newline(B) T=(R+10)3T=\frac{(R+10)}{3}\newline(C) T=R+310T=R+\frac{3}{10}\newline(D) T=R+103T=R+\frac{10}{3}

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Q. 3(TR)=103(T-R)=10, which of the following correctly expresses TT in terms of RR ? \newlineChoose 11 answer:\newline(A) T=(R+3)10T=\frac{(R+3)}{10}\newline(B) T=(R+10)3T=\frac{(R+10)}{3}\newline(C) T=R+310T=R+\frac{3}{10}\newline(D) T=R+103T=R+\frac{10}{3}
  1. Expand and Simplify: First, we need to isolate TT on one side of the equation. We start by expanding the left side of the equation.\newline3(TR)=3T3R3(T-R) = 3T - 3R\newlineThis gives us the equation 3T3R=103T - 3R = 10.
  2. Move Term Involving R: Next, we add 3R3R to both sides of the equation to move the term involving R to the right side.\newline3T3R+3R=10+3R3T - 3R + 3R = 10 + 3R\newlineThis simplifies to 3T=10+3R3T = 10 + 3R.
  3. Solve for T: Now, we divide both sides of the equation by 33 to solve for TT.\newline3T3=(10+3R)3\frac{3T}{3} = \frac{(10 + 3R)}{3}\newlineThis simplifies to T=(10+3R)3T = \frac{(10 + 3R)}{3}.
  4. Compare with Options: We compare the result with the given options to find the correct expression for TT in terms of RR. The correct expression is T=10+3R3T = \frac{10 + 3R}{3}, which matches option (D).

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