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3(4x-3)=4|x-(4x-3)|

3(4x3)=4x(4x3) 3(4 x-3)=4|x-(4 x-3)|

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Q. 3(4x3)=4x(4x3) 3(4 x-3)=4|x-(4 x-3)|
  1. Distribute and Simplify: First, let's simplify the left side of the equation by distributing the 33 into the parentheses.3(4x3)=12x93(4x-3) = 12x - 9
  2. Simplified Equation: Now, we have the simplified equation: 12x9=4x(4x3)12x - 9 = 4|x - (4x - 3)|
  3. Simplify Absolute Value: Next, we need to simplify the expression inside the absolute value on the right side of the equation. x(4x3)=x4x+3|x - (4x - 3)| = |x - 4x + 3|
  4. Further Simplification: Simplify the expression inside the absolute value further. x4x+3=3x+3|x - 4x + 3| = |-3x + 3|
  5. Consider Two Cases: Now, we have the equation:\newline12x9=43x+312x - 9 = 4|-3x + 3|\newlineWe need to consider two cases for the absolute value: one where the expression inside is positive, and one where it is negative.
  6. Case 11 Inequality: Case 11: The expression inside the absolute value is positive, i.e., 3x+30-3x + 3 \geq 0. We solve for xx in this inequality to find the range of xx for which this case applies. 3x+30-3x + 3 \geq 0 3x3-3x \geq -3 x1x \leq 1
  7. Solve Case 11 Equation: Now, we solve the equation for Case 11, assuming 3x+3-3x + 3 is positive.\newline12x9=4(3x+3)12x - 9 = 4(-3x + 3)
  8. Combine Like Terms: Distribute the 44 on the right side of the equation.12x9=12x+1212x - 9 = -12x + 12
  9. Isolate x Term: Add 12x12x to both sides of the equation to get all x terms on one side.\newline12x+12x9=12x+12x+1212x + 12x - 9 = -12x + 12x + 12\newline24x9=1224x - 9 = 12
  10. Solve for x: Add 99 to both sides of the equation to isolate the term with xx.\newline24x9+9=12+924x - 9 + 9 = 12 + 9\newline24x=2124x = 21
  11. Check Validity: Divide both sides by 2424 to solve for xx.\newlinex=2124x = \frac{21}{24}\newlinex=78x = \frac{7}{8}
  12. Case 22 Inequality: Now we need to check if x=78x = \frac{7}{8} satisfies the inequality x1x \leq 1 for Case 11.\newline781\frac{7}{8} \leq 1 is true, so x=78x = \frac{7}{8} is a valid solution for Case 11.
  13. Solve Case 22 Equation: Case 22: The expression inside the absolute value is negative, i.e., -3x + 3 < 0. We solve for xx in this inequality to find the range of xx for which this case applies. -3x + 3 < 0 -3x < -3 x > 1
  14. Remove Double Negative: Now, we solve the equation for Case 22, assuming 3x+3-3x + 3 is negative.12x9=4((3x+3))12x - 9 = 4(-(-3x + 3))
  15. Distribute and Simplify: Simplify the right side of the equation by removing the double negative. \newline12x9=4(3x3)12x - 9 = 4(3x - 3)
  16. Subtract Like Terms: Distribute the 44 on the right side of the equation.\newline12x9=12x1212x - 9 = 12x - 12
  17. Contradiction - No Solution: Subtract 12x12x from both sides of the equation to get all xx terms on one side.\newline12x12x9=12x12x1212x - 12x - 9 = 12x - 12x - 12\newline09=120 - 9 = -12
  18. Contradiction - No Solution: Subtract 12x12x from both sides of the equation to get all xx terms on one side.\newline12x12x9=12x12x1212x - 12x - 9 = 12x - 12x - 12\newline09=120 - 9 = -12 Simplify the equation.\newline9=12-9 = -12\newlineThis is a contradiction, which means there is no solution for xx in Case 22.

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