2x2+5x−k=0In the given equation, k is a constant. For what value of k does the equation have exactly one distinct real solution?Choose 1 answer:(A) −825(B) −45(C) 45(D) 825
Q. 2x2+5x−k=0In the given equation, k is a constant. For what value of k does the equation have exactly one distinct real solution?Choose 1 answer:(A) −825(B) −45(C) 45(D) 825
Quadratic Equation Discriminant: A quadratic equationax2+bx+c=0 has exactly one distinct real solution when its discriminant b2−4ac is equal to zero. This is because the discriminant determines the nature of the roots of the quadratic equation.
Given Equation and Variables: For the given equation 2x2+5x−k=0, a=2, b=5, and c=−k. We will set the discriminant equal to zero and solve for k. Discriminant: b2−4ac=0
Substitute Values: Substitute the values of a, b, and c into the discriminant equation:(5)2−4(2)(−k)=0
Simplify Equation: Simplify the equation: 25+8k=0
Solve for k: Solve for k:8k=−25k=−825
Final Solution: The value of k for which the equation has exactly one distinct real solution is −825.