Solve the quadratic equation 2x^2+18x-4=0

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Identify quadratic equation: Identify the quadratic equation to be solved. The given quadratic equation is 2x^2 + 18x - 4 = 0.Factor if possible: Factor the quadratic equation if possible. The quadratic equation does not factor nicely, so we will use the quadratic formula to find the roots. The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients from the quadratic equation ax^2 + bx + c = 0.Identify coefficients: Identify the coefficients a, b, and c from the quadratic equation. For the equation 2x^2 + 18x - 4 = 0, we have: a = 2, b = 18, and c = -4.Calculate discriminant: Calculate the discriminant (b^2 - 4ac). Discriminant = b^2 - 4ac Discriminant = (18)^2 - 4(2)(-4) Discriminant = 324 + 32 Discriminant = 356Calculate roots: Calculate the roots using the quadratic formula. x = (-b ± √(discriminant)) / (2a) x = (-18 ± √356) / (2 * 2) x = (-18 ± √356) / 4Simplify roots: Simplify the roots. x = (-18 + √356) / 4 or x = (-18 - √356) / 4 These are the most simplified forms of the roots as the square root of 356 cannot be simplified further.

Solve the quadratic equation $2x^2+18x-4=0$

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