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2689123÷35

$2689123 \div 35$

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Geometric sequences

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Q.

2689123 \div 35

Set up division: Set up the long division of $2689123$ by $35$ . To solve $2689123 \div 35$ , we will use long division.
Determine first division: Determine how many times $35$ goes into the first two digits of $2689123$ , which is $26$ . $\newline$ $35$ does not go into $26$ , so we will consider the first three digits, which is $268$ .
Find remainder: Determine how many times $35$ goes into $268$ . $\newline$ $35$ goes into $268$ a total of $7$ times because $7 \times 35 = 245$ , which is the closest multiple of $35$ that does not exceed $268$ .
Bring down next digit: Subtract $245$ from $268$ to find the remainder. $\newline$ $268 - 245 = 23$ .
Determine next division: Bring down the next digit from the dividend, which is $9$ , to make the new number $239$ .
Find next remainder: Determine how many times $35$ goes into $239$ . $35$ goes into $239$ a total of $6$ times because $6 \times 35 = 210$ , which is the closest multiple of $35$ that does not exceed $239$ .
Bring down next digit: Subtract $210$ from $239$ to find the remainder. $\newline$ $239 - 210 = 29$ .
Determine next division: Bring down the next digit from the dividend, which is $1$ , to make the new number $291$ .
Find next remainder: Determine how many times $35$ goes into $291$ . $35$ goes into $291$ a total of $8$ times because $8 \times 35 = 280$ , which is the closest multiple of $35$ that does not exceed $291$ .
Bring down next digit: Subtract $280$ from $291$ to find the remainder. $\newline$ $291 - 280 = 11$ .
Determine final division: Bring down the next digit from the dividend, which is $2$ , to make the new number $112$ .
Find final remainder: Determine how many times $35$ goes into $112$ . $35$ goes into $112$ a total of $3$ times because $3 \times 35 = 105$ , which is the closest multiple of $35$ that does not exceed $112$ .
Find final remainder: Determine how many times $35$ goes into $112$ . $35$ goes into $112$ a total of $3$ times because $3 \times 35 = 105$ , which is the closest multiple of $35$ that does not exceed $112$ . Subtract $105$ from $112$ to find the remainder. $112$ $0$ .
Find final remainder: Determine how many times $35$ goes into $112$ . $35$ goes into $112$ a total of $3$ times because $3 \times 35 = 105$ , which is the closest multiple of $35$ that does not exceed $112$ . Subtract $105$ from $112$ to find the remainder. $112$ $0$ . Bring down the next digit from the dividend, which is $3$ , to make the new number $112$ $2$ .
Find final remainder: Determine how many times $35$ goes into $112$ . $35$ goes into $112$ a total of $3$ times because $3 \times 35 = 105$ , which is the closest multiple of $35$ that does not exceed $112$ . Subtract $105$ from $112$ to find the remainder. $112$ $0$ . Bring down the next digit from the dividend, which is $3$ , to make the new number $112$ $2$ . Determine how many times $35$ goes into $112$ $2$ . $35$ goes into $112$ $2$ a total of $112$ $7$ times because $112$ $8$ , which is the closest multiple of $35$ that does not exceed $112$ $2$ .
Find final remainder: Determine how many times $35$ goes into $112$ . $35$ goes into $112$ a total of $3$ times because $3 \times 35 = 105$ , which is the closest multiple of $35$ that does not exceed $112$ . Subtract $105$ from $112$ to find the remainder. $112$ $0$ . Bring down the next digit from the dividend, which is $3$ , to make the new number $112$ $2$ . Determine how many times $35$ goes into $112$ $2$ . $35$ goes into $112$ $2$ a total of $112$ $7$ times because $112$ $8$ , which is the closest multiple of $35$ that does not exceed $112$ $2$ . Subtract $35$ $1$ from $112$ $2$ to find the remainder. $35$ $3$ . This is the final remainder since there are no more digits to bring down.

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