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200000=P ×(1+(13)/(100))^(10)

200000=P×(1+13100)10 200000=P \times\left(1+\frac{13}{100}\right)^{10}

Full solution

Q. 200000=P×(1+13100)10 200000=P \times\left(1+\frac{13}{100}\right)^{10}
  1. Set up compound interest formula: To solve for the initial principal PP, we need to rearrange the compound interest formula to solve for PP. The formula is given by A=P(1+r/n)(nt)A = P(1 + r/n)^{(nt)}, where AA is the amount of money accumulated after nn years, including interest, PP is the principal amount, rr is the annual interest rate (decimal), nn is the number of times that interest is compounded per year, and tt is the time the money is invested for in years. In this problem, A=200,000A = 200,000, PP00, PP11 (since the interest is compounded annually), and PP22 years.
  2. Plug in given values: First, we plug in the given values into the formula: 200,000=P×(1+0.13)10200,000 = P \times (1 + 0.13)^{10}.
  3. Simplify expression: Next, we simplify the expression inside the parentheses: 1+0.13=1.131 + 0.13 = 1.13.
  4. Calculate value: Now, we raise 1.131.13 to the power of 1010: (1.13)10(1.13)^{10}. Using a calculator, we find that (1.13)103.39357057(1.13)^{10} \approx 3.39357057.
  5. Divide both sides: We then divide both sides of the equation by 3.393570573.39357057 to solve for PP: P=200,0003.39357057.P = \frac{200,000}{3.39357057}.
  6. Perform division: Finally, we perform the division: P200,0003.3935705758,946.12P \approx \frac{200,000}{3.39357057} \approx 58,946.12.

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