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Let’s check out your problem:
20
b
−
2
b
+
3
b
+
x
20 b-2 b+3 b+x
20
b
−
2
b
+
3
b
+
x
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Math Problems
Algebra 2
Factor polynomials
Full solution
Q.
20
b
−
2
b
+
3
b
+
x
20 b-2 b+3 b+x
20
b
−
2
b
+
3
b
+
x
Combine Like Terms:
Step Title: Combine Like Terms
\newline
Concise Step Description: Combine the terms with the variable
b
b
b
and leave the term with
x
x
x
as it is since it is not like the other terms.
\newline
Step Calculation:
20
b
−
2
b
+
3
b
=
(
20
−
2
+
3
)
b
=
21
b
20b - 2b + 3b = (20 - 2 + 3)b = 21b
20
b
−
2
b
+
3
b
=
(
20
−
2
+
3
)
b
=
21
b
\newline
Step Output:
21
b
+
x
21b + x
21
b
+
x
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Question
Factor out the greatest common factor. If the greatest common factor is
1
1
1
, just retype the polynomial.
\newline
4
x
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−
6
x
2
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4
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−
6
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\newline
______
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Question
Factor
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completely.
\newline
All factors in your answer should have integer coefficients.
\newline
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Question
Find the binomial that completes the factorization.
\newline
t
3
+
u
3
=
(
‾
)
(
t
2
−
t
u
+
u
2
)
t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)
t
3
+
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3
=
(
)
(
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−
t
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Question
Factor.
\newline
g
2
−
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g
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g^2 - 11g + 18
g
2
−
11
g
+
18
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Question
Factor.
\newline
2
y
3
−
y
2
+
16
y
−
8
2y^3 - y^2 + 16y - 8
2
y
3
−
y
2
+
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y
−
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\newline
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\newline
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Posted 9 months ago
Question
Factor.
\newline
2
x
8
+
7
x
2
2x^8 + 7x^2
2
x
8
+
7
x
2
\newline
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Posted 10 months ago
Question
Factor.
\newline
9
y
12
+
4
y
5
−
y
2
9y^{12} + 4y^5 - y^2
9
y
12
+
4
y
5
−
y
2
\newline
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Posted 9 months ago
Question
Factor.
\newline
6
a
4
+
3
a
3
−
a
+
2
6a^4 + 3a^3 - a + 2
6
a
4
+
3
a
3
−
a
+
2
\newline
_____
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Posted 9 months ago
Question
Factor.
\newline
4
c
7
−
2
c
5
+
c
2
−
5
4c^7 - 2c^5 + c^2 - 5
4
c
7
−
2
c
5
+
c
2
−
5
\newline
_____
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Posted 9 months ago
Question
Factor.
\newline
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
7m^9 + 2m^6 - m^3 + 4m - 10
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
\newline
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Related topics
Algebra - Order of Operations
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Common Multiple
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