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19-38 y=76 x

24 x=-6(2y-1)
Consider the system of equations. How many solutions 
(x,y) does this system have?
Choose 1 answer:
(A) 0
(B) Exactly 1
(c) Exactly 2
(D) Infinitely many

1938y=76x 19-38 y=76 x \newline24x=6(2y1) 24 x=-6(2 y-1) \newlineConsider the system of equations. How many solutions (x,y) (x, y) does this system have?\newlineChoose 11 answer:\newline(A) 00\newline(B) Exactly 11\newline(C) Exactly 22\newline(D) Infinitely many

Full solution

Q. 1938y=76x 19-38 y=76 x \newline24x=6(2y1) 24 x=-6(2 y-1) \newlineConsider the system of equations. How many solutions (x,y) (x, y) does this system have?\newlineChoose 11 answer:\newline(A) 00\newline(B) Exactly 11\newline(C) Exactly 22\newline(D) Infinitely many
  1. Simplify first equation: First, let's simplify each equation to see if we can find a relationship between xx and yy. Starting with the first equation: 1938y=76x19 - 38y = 76x We can divide both sides by 1919 to simplify: 12y=4x1 - 2y = 4x Now, let's isolate yy: 2y=14x2y = 1 - 4x y=14x2y = \frac{1 - 4x}{2}
  2. Isolate yy in first equation: Next, let's simplify the second equation:\newline24x=6(2y1)24x = -6(2y - 1)\newlineWe can distribute the 6-6:\newline24x=12y+624x = -12y + 6\newlineNow, let's isolate yy:\newline12y=24x6-12y = 24x - 6\newliney=(624x)/12y = (6 - 24x) / -12\newliney=1/2+2xy = -1/2 + 2x
  3. Simplify second equation: Now we have two expressions for yy:y=14x2y = \frac{1 - 4x}{2}y=12+2xy = -\frac{1}{2} + 2xLet's set them equal to each other to see if there is a solution for xx that satisfies both equations:14x2=12+2x\frac{1 - 4x}{2} = -\frac{1}{2} + 2x
  4. Isolate y in second equation: To solve for x, we can multiply both sides by 22 to get rid of the denominators:\newline14x=1+4x1 - 4x = -1 + 4x\newlineNow, let's add 44x to both sides:\newline1=1+8x1 = -1 + 8x\newlineThen, add 11 to both sides:\newline2=8x2 = 8x\newlineNow, divide both sides by 88:\newlinex=28x = \frac{2}{8}\newlinex=14x = \frac{1}{4}
  5. Set equations equal to each other: Now that we have the value for xx, let's substitute it back into one of the expressions for yy to find the corresponding yy value:\newliney=14(14)2y = \frac{1 - 4(\frac{1}{4})}{2}\newliney=112y = \frac{1 - 1}{2}\newliney=02y = \frac{0}{2}\newliney=0y = 0

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