Solve for $x$: 15=-(5)/(3)x

Isolate variable x: Isolate the variable x on one side of the equation. To do this, we need to get rid of the fraction by multiplying both sides of the equation by the reciprocal of -5/3, which is -3/5. Calculation: 15 * (-3/5) = -(5/3)x * (-3/5)Perform multiplication: Perform the multiplication on both sides. On the left side, 15 multiplied by -3/5 equals -9. On the right side, the -5/3 and -3/5 cancel each other out, leaving us with x. Calculation: -9 = xWrite solution set: Write the solution set. The solution set is the value of x that satisfies the equation. Since we have found that x equals -9, the solution set is {-9}.

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Solve for $x$ : $15 = -\frac{5}{3}x$ $\newline$

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Algebra 2

Sin, cos, and tan of special angles

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Q. Solve for

x

15 = -\frac{5}{3}x

\newline

Isolate variable x: Isolate the variable $x$ on one side of the equation. $\newline$ To do this, we need to get rid of the fraction by multiplying both sides of the equation by the reciprocal of $-\frac{5}{3}$ , which is $-\frac{3}{5}$ . $\newline$ Calculation: $15 \times (-\frac{3}{5}) = -\left(\frac{5}{3}\right)x \times (-\frac{3}{5})$
Perform multiplication: Perform the multiplication on both sides. $\newline$ On the left side, $15$ multiplied by $-\frac{3}{5}$ equals $-9$ . $\newline$ On the right side, the $-\frac{5}{3}$ and $-\frac{3}{5}$ cancel each other out, leaving us with $x$ . $\newline$ Calculation: $-9 = x$
Write solution set: Write the solution set. $\newline$ The solution set is the value of $x$ that satisfies the equation. Since we have found that $x$ equals $-9$ , the solution set is $\{-9\}$ .