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13^(2x)-5*3^(x)+6=0

132x53x+6=0 13^{2 x}-5 \cdot 3^{x}+6=0

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Q. 132x53x+6=0 13^{2 x}-5 \cdot 3^{x}+6=0
  1. Identify Equation Type: Step Title: Identify the Type of Equation\newlineConcise Step Description: Determine the type of equation we are dealing with to apply the appropriate method for solving it.\newlineStep Calculation: The equation is 132x53x+6=013^{2x} - 5\cdot3^{x} + 6 = 0. This is not a standard quadratic equation due to the different bases of the exponents. However, we can try to transform it into a quadratic form by substitution if possible.
  2. Find Substitution: Step Title: Look for a Substitution\newlineConcise Step Description: Find a substitution that can transform the equation into a quadratic form.\newlineStep Calculation: Let's denote 3x3^{x} as 'yy'. Then, 132x13^{2x} can be written as (3x)2(3^{x})^2, which is y2y^2. The equation now looks like y25y+6=0y^2 - 5y + 6 = 0, which is a quadratic equation in terms of 'yy'.
  3. Factor Quadratic Equation: Step Title: Factor the Quadratic Equation\newlineConcise Step Description: Factor the quadratic equation obtained after the substitution.\newlineStep Calculation: We need to find two numbers that multiply to 66 (the constant term) and add up to 5-5 (the coefficient of the 'yy' term). The numbers that satisfy these conditions are 2-2 and 3-3. Therefore, the factored form is (y2)(y3)=0(y - 2)(y - 3) = 0.
  4. Solve for Substituted Variable: Step Title: Solve for the Substituted Variable\newlineConcise Step Description: Solve the factored equation for the substituted variable ' extit{y}'.\newlineStep Calculation: We have two possible solutions for ' extit{y}': y2=0y - 2 = 0 or y3=0y - 3 = 0. This gives us y=2y = 2 or y=3y = 3.
  5. Back-Substitute for 'x': Step Title: Back-Substitute to Solve for 'x' Concise Step Description: Replace 'y' with 3x3^{x} and solve for 'x'. Step Calculation: Since y=3xy = 3^{x}, we have two equations: 3x=23^{x} = 2 and 3x=33^{x} = 3. Solving for 'x' gives us x=log3(2)x = \log_3(2) and x=log3(3)x = \log_3(3). The second equation simplifies to x=1x = 1 because 31=33^{1} = 3.
  6. Solve Logarithmic Equations: Step Title: Solve the Logarithmic Equations\newlineConcise Step Description: Solve the logarithmic equations to find the values of xx.\newlineStep Calculation: The first equation is x=log3(2)x = \log_3(2). This cannot be simplified further without a calculator. The second equation has already been simplified to x=1x = 1.