Carter traveled 95 miles from Sartell to Target Field by car for part of the way and then took the Lioit Rail Train for the remainder of the trip. The car was traveling an average rate of 60mph and we Lioit Rall Train averaged 90mph. If the total trip took 1.5 hours. How long did Carter travel by train?
Q. Carter traveled 95 miles from Sartell to Target Field by car for part of the way and then took the Lioit Rail Train for the remainder of the trip. The car was traveling an average rate of 60mph and we Lioit Rall Train averaged 90mph. If the total trip took 1.5 hours. How long did Carter travel by train?
Define travel time equation: Let's define the time Carter traveled by car as tc hours and by train as tt hours. The total travel time is given as 1.5 hours. So, we write the equation:tc+tt=1.5
Use rate-time-distance relationship: We know the car traveled at 60 mph and the train at 90 mph. Let's assume the distance traveled by car is dc miles and by train is dt miles. Using the rate-time-distance relationship:dc=60tcdt=90tt
Write total distance equation: Since the total distance is 95 miles, we can write another equation:dc+dt=95Substituting the expressions for dc and dt from the previous step:60tc+90tt=95
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