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Carter traveled 9595 miles from Sartell to Target Field by car for part of the way and then took the Lioit Rail Train for the remainder of the trip. The car was traveling an average rate of 6060mph and we Lioit Rall Train averaged \newline9090mph. If the total trip took 1.51.5 hours. How long did Carter travel by train?

Full solution

Q. Carter traveled 9595 miles from Sartell to Target Field by car for part of the way and then took the Lioit Rail Train for the remainder of the trip. The car was traveling an average rate of 6060mph and we Lioit Rall Train averaged \newline9090mph. If the total trip took 1.51.5 hours. How long did Carter travel by train?
  1. Define travel time equation: Let's define the time Carter traveled by car as tc t_c hours and by train as tt t_t hours. The total travel time is given as 11.55 hours. So, we write the equation:\newlinetc+tt=1.5 t_c + t_t = 1.5
  2. Use rate-time-distance relationship: We know the car traveled at 6060 mph and the train at 9090 mph. Let's assume the distance traveled by car is dc d_c miles and by train is dt d_t miles. Using the rate-time-distance relationship:\newlinedc=60tc d_c = 60t_c \newlinedt=90tt d_t = 90t_t
  3. Write total distance equation: Since the total distance is 9595 miles, we can write another equation:\newlinedc+dt=95 d_c + d_t = 95 \newlineSubstituting the expressions for dc d_c and dt d_t from the previous step:\newline60tc+90tt=95 60t_c + 90t_t = 95

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