Q. 12t=4v−3 and −6t=4v+6. If (t,v) is the solution to the system of equations, what is the value of t−v?
Write Equations: Write down the system of equations.We have the following system of equations:12t=4v−3−6t=4v+6
Modify Second Equation: Multiply the second equation by 2 to make the coefficients of t the same in both equations.Multiplying the second equation by 2 gives us:−12t=8v+12
Eliminate Variable: Add the modified second equation to the first equation to eliminate t. Adding the equations we get: 12t+(−12t)=(4v−3)+(8v+12)0=12v+9
Solve for v: Solve for v.Subtract 9 from both sides to isolate the term with v:12v=−9Divide both sides by 12 to solve for v:v=−129Simplify the fraction:v=−43
Substitute and Solve for t: Substitute the value of v into one of the original equations to solve for t. Let's use the first equation: 12t=4v−3 Substitute v with −43: 12t=4(−43)−3
Calculate t−v: Simplify the equation and solve for t. 12t=−3−3 12t=−6 Divide both sides by 12 to solve for t: t=12−6 Simplify the fraction: t=2−1
Calculate t−v: Simplify the equation and solve for t.12t=−3−312t=−6Divide both sides by 12 to solve for t:t=−126Simplify the fraction:t=−21Calculate t−v.t−v=(−21)−(−43)To subtract fractions, find a common denominator. In this case, the common denominator is t0:t1t2t3
More problems from Evaluate variable expressions with decimals, fractions, and mixed numbers