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12 y(3y^(4)-7y^(2)+1)

12y(3y47y2+1) 12 y\left(3 y^{4}-7 y^{2}+1\right)

Full solution

Q. 12y(3y47y2+1) 12 y\left(3 y^{4}-7 y^{2}+1\right)
  1. Distribute 12y12y to 3y43y^{4}: We need to distribute the term 12y12y across the terms inside the parentheses.\newline12y×3y4=36y512y \times 3y^{4} = 36y^{5}
  2. Distribute 12y12y to 7y2-7y^{2}: Next, distribute 12y12y to the second term inside the parentheses.\newline12y×(7y2)=84y312y \times (-7y^{2}) = -84y^{3}
  3. Distribute 12y12y to 11: Finally, distribute 12y12y to the last term inside the parentheses.\newline12y×1=12y12y \times 1 = 12y
  4. Combine distributed terms: Combine all the distributed terms to get the final simplified expression.\newline36y584y3+12y36y^{5} - 84y^{3} + 12y

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