Q. 1: Solve the following exponential equation4x+2x+2−12=0
Identify Equation Structure: Let's first identify the structure of the equation and see if we can simplify it using properties of exponents.The equation is 4x+2x+2−12=0.We notice that 4 is a power of 2, specifically 4=22, so we can rewrite 4x as (22)x=22x.Also, 2x+2 can be written as 2x⋅22=4⋅2x.Now, let's rewrite the equation with these observations.
Rewrite Using Exponents: Rewrite the equation using the properties of exponents. 4x+2x+2−12=0 becomes 22x+4⋅2x−12=0. Now, we have an equation that resembles a quadratic equation in form of 2x. Let's set y=2x and rewrite the equation in terms of y.
Substitute and Rewrite: Substitute y=2x into the equation.The equation becomes y2+4y−12=0.Now, we have a quadratic equation in y, which we can solve using factoring, completing the square, or the quadratic formula.Let's try to factor the quadratic equation.
Factor Quadratic Equation: Factor the quadratic equation y2+4y−12=0. We look for two numbers that multiply to −12 and add up to 4. The numbers 6 and −2 satisfy these conditions. So, we can write the equation as (y+6)(y−2)=0. Now, we can find the values of y by setting each factor equal to zero.
Solve for y: Solve for y from the factors(y+6)=0 and (y−2)=0. For the first factor, y+6=0, we get y=−6. For the second factor, y−2=0, we get y=2. Now we have two possible values for y, which are y=−6 and y=2.
Solve for x: Recall that y=2x. We will now solve for x using the values of y we found.First, let's take y=−6. Since 2x is always positive, there is no real number x such that 2x=−6. Therefore, y=−6 does not give us a valid solution for x.Now, let's take y=2. We need to solve x0.
Solve for x: Recall that y=2x. We will now solve for x using the values of y we found.First, let's take y=−6. Since 2x is always positive, there is no real number x such that 2x=−6. Therefore, y=−6 does not give us a valid solution for x.Now, let's take y=2x0. We need to solve y=2x1.Solve the equation y=2x1.Since the bases are the same, we can equate the exponents.This gives us y=2x3.So, the solution to the equation y=2x1 is y=2x3.
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