Q. y=−x−11y=x2−5x−7Which of the following is a solution to the system of equations?Choose 1 answer:(A) (−2,−9)(B) (0,−7)(C) (2,−13)(D) (3,−13)
Plug x-values in second equation: First, let's plug in the x-values from each option into the second equation y=x2−5x−7 and see if they match the y-values given.
Option (A): Option (A): For x=−2, y=(−2)2−5(−2)−7=4+10−7=7, but the option says y=−9, so this ain't right.
Option (B): Option (B): For x=0, y=02−5(0)−7=−7, which matches the y-value given in the option, but we gotta check the first equation too.
Option (C): Plug x=0 into the first equation y=−x−11, we get y=−0−11=−11, which doesn't match the y-value from option (B), so this ain't it either.
Option (D): Option (C): For x=2, y=22−5(2)−7=4−10−7=−13, which matches the y-value given in the option, let's check the first equation.
Option (D): Option (C): For x=2, y=22−5(2)−7=4−10−7=−13, which matches the y-value given in the option, let's check the first equation.Plug x=2 into the first equation y=−x−11, we get y=−2−11=−13, which matches the y-value from option (C), so this looks good, but let's check the last option to be sure.
Option (D): Option (C): For x=2, y=22−5(2)−7=4−10−7=−13, which matches the y-value given in the option, let's check the first equation.Plug x=2 into the first equation y=−x−11, we get y=−2−11=−13, which matches the y-value from option (C), so this looks good, but let's check the last option to be sure.Option (D): For x=3, y=32−5(3)−7=9−15−7=−13, which matches the y-value given in the option, but we gotta check the first equation too.
Option (D): Option (C): For x=2, y=22−5(2)−7=4−10−7=−13, which matches the y-value given in the option, let's check the first equation.Plug x=2 into the first equation y=−x−11, we get y=−2−11=−13, which matches the y-value from option (C), so this looks good, but let's check the last option to be sure.Option (D): For x=3, y=32−5(3)−7=9−15−7=−13, which matches the y-value given in the option, but we gotta check the first equation too.Plug x=3 into the first equation y=−x−11, we get y=22−5(2)−7=4−10−7=−132, but the option says y=22−5(2)−7=4−10−7=−133, so there's a mistake here, and option (D) is wrong.