Q. If (x,y) is a solution to the system of equations shown, what is the product of the y-coordinates of the solutions?x2+y2=9x+y=3
Write Equations: Write down the given system of equations.We have the following system of equations:1) x2+y2=92) x+y=3
Solve for y: Solve the second equation for one of the variables.Let's solve for y:y=3−x
Substitute and Simplify: Substitute the expression for y from Step 2 into the first equation.Substituting y=3−x into x2+y2=9 gives us:x2+(3−x)2=9
Expand and Combine Terms: Expand the squared term and simplify the equation.Expanding (3−x)2 gives us 9−6x+x2, so the equation becomes:x2+9−6x+x2=9Combining like terms, we get:2x2−6x+9=9
Subtract to Simplify: Subtract 9 from both sides to simplify the equation further.2x2−6x+9−9=9−9This simplifies to:2x2−6x=0
Factor Out x: Factor out the common term x.x(2x−6)=0
Solve for x: Solve for x using the zero product property.Setting each factor equal to zero gives us two possible solutions for x:1) x=02) 2x−6=0 which simplifies to x=3
Find y-Values: Find the corresponding y-values for each x-value.Using y=3−x, we find the y-values:For x=0, y=3−0=3For x=3, y=3−3=0
Calculate Product: Calculate the product of the y-coordinates.The y-coordinates are 3 and 0. The product of these is:3×0=0
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