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{:[x+y=11],[x+3=y]:}
Bex and Yin are running errands together. The given system of equations relates 
x, the number of errands Bex has to run, and 
y, the number of errands Yin has to run. Based on the system, which of the following statements is true?
Choose 1 answer:
(A) Bex has 11 more errands to run than Yin does.
(B) Yin has 11 more errands to run than Bex does.
(C) Bex has 3 more errands to run than Yin does.
(D) Yin has 3 more errands to run than Bex does.

x+y=11x+3=y \begin{array}{l} x+y=11 \\ x+3=y \end{array} \newlineBex and Yin are running errands together. The given system of equations relates x x , the number of errands Bex has to run, and y y , the number of errands Yin has to run. Based on the system, which of the following statements is true?\newlineChoose 11 answer:\newline(A) Bex has 1111 more errands to run than Yin does.\newline(B) Yin has 1111 more errands to run than Bex does.\newline(C) Bex has 33 more errands to run than Yin does.\newline(D) Yin has 33 more errands to run than Bex does.

Full solution

Q. x+y=11x+3=y \begin{array}{l} x+y=11 \\ x+3=y \end{array} \newlineBex and Yin are running errands together. The given system of equations relates x x , the number of errands Bex has to run, and y y , the number of errands Yin has to run. Based on the system, which of the following statements is true?\newlineChoose 11 answer:\newline(A) Bex has 1111 more errands to run than Yin does.\newline(B) Yin has 1111 more errands to run than Bex does.\newline(C) Bex has 33 more errands to run than Yin does.\newline(D) Yin has 33 more errands to run than Bex does.
  1. Analyze Equations: Analyze the given system of equations.\newlineWe have two equations:\newline11. x+y=11x + y = 11\newline22. x+3=yx + 3 = y\newlineWe need to find the relationship between the number of errands Bex (xx) and Yin (yy) have to run.
  2. Substitute and Simplify: Substitute the second equation into the first equation.\newlineFrom the second equation, we can express yy as y=x+3y = x + 3. Now we substitute this into the first equation:\newlinex+(x+3)=11x + (x + 3) = 11
  3. Solve for x: Solve for x.\newlineCombine like terms:\newline2x+3=112x + 3 = 11\newlineSubtract 33 from both sides:\newline2x=1132x = 11 - 3\newline2x=82x = 8\newlineDivide both sides by 22:\newlinex=82x = \frac{8}{2}\newlinex=4x = 4
  4. Solve for y: Solve for y using the value of xx.\newlineNow that we know x=4x = 4, we can substitute it back into the second equation to find yy:\newliney=x+3y = x + 3\newliney=4+3y = 4 + 3\newliney=7y = 7
  5. Determine Relationship: Determine the correct statement based on the values of xx and yy. We have found that Bex (xx) has to run 44 errands and Yin (yy) has to run 77 errands. Since y=x+3y = x + 3, it means Yin has 33 more errands to run than Bex does.

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