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xx+3=x+2x+62\frac{x}{x+3}=\frac{x+2}{x+\frac{6}{2}} Find `x`

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Q. xx+3=x+2x+62\frac{x}{x+3}=\frac{x+2}{x+\frac{6}{2}} Find `x`
  1. Simplify Equation: First, let's simplify the equation by getting rid of the colon, which represents division. The equation (x+6:2)(x+6:2) can be simplified to (x+6)/2(x+6)/2.
  2. Cross-Multiply Fractions: Now, we have the equation (\frac{x}{x+3} = \frac{x+2}{\frac{x+6}{2}})\. To solve for \$x, we need to cross-multiply to get rid of the fractions.
  3. Expand Equations: Cross-multiplying gives us 2x×(x+3)=(x+2)×(x+6)2x \times (x+3) = (x+2) \times (x+6).
  4. Rearrange Terms: Expanding both sides of the equation, we get 2x2+6x=x2+8x+122x^2 + 6x = x^2 + 8x + 12.
  5. Combine Like Terms: Now, let's move all terms to one side of the equation to set it equal to zero. Subtract x2x^2 from both sides and subtract 8x8x from both sides to get 2x2+6xx28x=122x^2 + 6x - x^2 - 8x = 12.
  6. Factor Quadratic Equation: Simplify the equation by combining like terms to get x22x12=0x^2 - 2x - 12 = 0.
  7. Set Factors Equal: Now we need to factor the quadratic equation. The factors of 12-12 that add up to 2-2 are 6-6 and +4+4. So we can write the equation as (x6)(x+4)=0(x - 6)(x + 4) = 0.
  8. Solve for xx: Setting each factor equal to zero gives us the possible solutions for xx: x6=0x - 6 = 0 or x+4=0x + 4 = 0.
  9. Solve for x: Setting each factor equal to zero gives us the possible solutions for x: x6=0x - 6 = 0 or x+4=0x + 4 = 0. Solving each equation for x gives us x=6x = 6 or x=4x = -4.

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