Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

(x^(-4)y^(2))^(-3)*x^(4)y^(2)

(x4y2)3x4y2 \left(x^{-4} y^{2}\right)^{-3} \cdot x^{4} y^{2}

Full solution

Q. (x4y2)3x4y2 \left(x^{-4} y^{2}\right)^{-3} \cdot x^{4} y^{2}
  1. Apply Power Rule: Apply the power of a power rule to the first term.\newlineThe power of a power rule states that (am)n=amn(a^m)^n = a^{m*n}. We will apply this rule to the term (x4y2)3(x^{-4}y^{2})^{-3}.\newline(x4y2)3=x43y23(x^{-4}y^{2})^{-3} = x^{-4*-3}y^{2*-3}\newline= x12y6x^{12}y^{-6}
  2. Multiply Terms: Multiply the simplified first term by the second term.\newlineNow we multiply x12y6x^{12}y^{-6} by x4y2x^{4}y^{2}.\newlinex12y6×x4y2x^{12}y^{-6} \times x^{4}y^{2}
  3. Apply Product Rule: Apply the product of powers rule to the xx terms and yy terms separately.\newlineThe product of powers rule states that aman=a(m+n)a^m \cdot a^n = a^{(m+n)} when the bases are the same. We will apply this rule to the xx terms and yy terms separately.\newlinex12x4=x(12+4)x^{12} \cdot x^{4} = x^{(12+4)}\newliney6y2=y(6+2)y^{-6} \cdot y^{2} = y^{(-6+2)}
  4. Add Exponents: Perform the addition of exponents for both xx and yy. Now we add the exponents for xx and yy. x(12+4)=x16x^{(12+4)} = x^{16} y(6+2)=y4y^{(-6+2)} = y^{-4}
  5. Combine Results: Combine the results for xx and yy. Now we combine the results for xx and yy to get the final simplified expression. x16y4x^{16} \cdot y^{-4}
  6. Check Simplifications: Check for any possible simplifications or errors.\newlineThe expression x16y4x^{16} \cdot y^{-4} is already in its simplest form, and there are no further simplifications possible. There are no math errors in the previous steps.

More problems from Multiplication with rational exponents