(x+3)2+(y−4)2=9A circle in the xy-plane has the equation shown. If the x coordinate of a point on the circle is −3 , what is a possible corresponding y-coordinate?
Q. (x+3)2+(y−4)2=9A circle in the xy-plane has the equation shown. If the x coordinate of a point on the circle is −3 , what is a possible corresponding y-coordinate?
Substitute and Solve: We are given the equation of a circle(x+3)2+(y−4)2=9 and we need to find the y-coordinate when x=−3. First, let's substitute x=−3 into the equation and solve for y. (−3+3)2+(y−4)2=9
Simplify Left Side: Now, we simplify the left side of the equation.(0)2+(y−4)2=90+(y−4)2=9(y−4)2=9
Take Square Root: Next, we take the square root of both sides of the equation to solve for y−4.(y−4)2=±9y−4=±3
Two Possible Solutions: We have two possible solutions for y−4: y−4=3 or y−4=−3. Let's solve for y in both cases. First case: y−4=3y=3+4y=7
First Case Solution: Second case: y−4=−3y=−3+4y=1
Second Case Solution: We have found two possible y-coordinates for the point on the circle when x=−3: y=7 and y=1.
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