(x^(2)+6x-30)/(30-6x-x^(2)) Which expression is equivalent to the given expression for all x^(2)+6x-30!=0 ? Choose 1 answer: (A) -1 (B) 1 (C) 0 (D) ((x+6)(x-5))/((6-x)(5+x))

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(x^(2)+6x-30)/(30-6x-x^(2)) Which expression is equivalent to the given expression for all  x^(2)+6x-30!=0 ? Choose 1 answer: (A) -1 (B) 1 (C) 0 (D)  ((x+6)(x-5))/((6-x)(5+x))

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Factor Numerator: Factor the numerator x^2 + 6x - 30. To factor the quadratic expression, we look for two numbers that multiply to -30 and add to 6. These numbers are 10 and -5. So, x^2 + 6x - 30 can be factored as (x + 10)(x - 5).Factor Denominator: Factor the denominator 30 - 6x - x^2. Notice that this is a quadratic expression that can be rewritten in standard form as -x^2 - 6x + 30. To factor this expression, we look for two numbers that multiply to 30 and add to -6. These numbers are -10 and 5. However, since the quadratic has a negative leading coefficient, we can factor out a negative sign to make it easier to see the factors: -(x^2 + 6x - 30). Now, we can factor the expression inside the parentheses as -(x + 10)(x - 5).Write Expression: Write the original expression with the factored numerator and denominator. The original expression (x^2 + 6x - 30)/(30 - 6x - x^2) can now be written as ((x + 10)(x - 5))/(-(x + 10)(x - 5)).Simplify Expression: Simplify the expression by canceling out common factors. We can cancel out the common factors (x + 10)(x - 5) in the numerator and the denominator, but we must also remember the negative sign in the denominator. After canceling, we are left with -1, since the negative sign does not cancel out.

$\frac{x^{2}+6 x-30}{30-6 x-x^{2}}$ $\newline$ Which expression is equivalent to the given expression for all $x^{2}+6 x-30 \neq 0$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $-1$ $\newline$ (B) $1$ $\newline$ (C) $0$ $\newline$ (D) $\frac{(x+6)(x-5)}{(6-x)(5+x)}$

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