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(x+1)236=0(x + 1)^2 - 36 = 0

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Q. (x+1)236=0(x + 1)^2 - 36 = 0
  1. Identify Equation: Step Title: Identify the Equation\newlineConcise Step Description: Recognize the equation as a difference of squares.\newlineCalculation: (x+1)236(x + 1)^2 - 36 can be seen as a2b2a^2 - b^2 where a=(x+1)a = (x + 1) and b=6b = 6.
  2. Apply Formula: Step Title: Apply the Difference of Squares Formula\newlineConcise Step Description: Use the difference of squares formula, which is a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b).\newlineCalculation: (x+1+6)(x+16)=(x+7)(x5)(x + 1 + 6)(x + 1 - 6) = (x + 7)(x - 5).
  3. Set Equal to Zero: Step Title: Set Each Factor Equal to Zero\newlineConcise Step Description: Since the product of the factors equals zero, set each factor equal to zero to find the solutions for xx.\newlineCalculation: x+7=0x + 7 = 0 and x5=0x - 5 = 0.
  4. Solve for xx: Step Title: Solve for xx\newlineConcise Step Description: Solve each equation for xx.\newlineCalculation: x=7x = -7 and x=5x = 5.