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Write an expression to describe the sequence below. Use n n to represent the position of a term in the sequence, where n=1 n = 1 for the first term. −55,−54,−53,−52,… -55, -54, -53, -52, \ldots an=‾ a_n = \underline{\hspace{3em}}

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Q. Write an expression to describe the sequence below. Use n n to represent the position of a term in the sequence, where n=1 n = 1 for the first term. −55,−54,−53,−52,… -55, -54, -53, -52, \ldots an=‾ a_n = \underline{\hspace{3em}}
  1. Sequence Type: We have: \newline−55,−54,−53,−52,…-55, -54, -53, -52, \ldots \newlineIs the given sequence geometric or arithmetic? \newline−55,−54,−53,−52,…-55, -54, -53, -52, \ldots \newlineHere, there is a common difference between consecutive terms.\newlineThe given sequence is arithmetic.
  2. Find a1a_1 and dd: Determine the values of a1a_1 and dd of the sequence. \newlineThe first term, a1=−55a_1 = -55 \newlineCommon difference, d=−54−(−55)=−54+55=1d = -54 - (-55) = -54 + 55 = 1
  3. Expression for Sequence: We have: \newlinean=a1+(n−1)da_n = a_1 + (n-1)d \newlinea1=−55a_1 = -55 \newlined=1d = 1 \newlineWrite an expression to describe −55-55, −54-54, −53-53, −52-52, ... \newlinean=a1+(n−1)da_n = a_1 + (n-1)d \newlinean=−55+(n−1)×1a_n = -55 + (n-1) \times 1 \newlinean=−55+n−1a_n = -55 + n - 1 \newlinean=n−56a_n = n - 56

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