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Is (1,1)(1,1) a solution to this system of equations? 4x+10y=144x + 10y = 14 x+6y=7x + 6y = 7 Choices: \newline[[yes]\newline[no]]

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Q. Is (1,1)(1,1) a solution to this system of equations? 4x+10y=144x + 10y = 14 x+6y=7x + 6y = 7 Choices: \newline[[yes]\newline[no]]
  1. Check First Equation: Step 11: Check if (1,1)(1,1) satisfies the first equation 4x+10y=144x + 10y = 14.\newlineCalculation: 4(1)+10(1)=4+10=144(1) + 10(1) = 4 + 10 = 14.\newline14=1414 = 14, so it satisfies the first equation.
  2. Check Second Equation: Step 22: Check if 1,11,1 satisfies the second equation x+6y=7x + 6y = 7.\newlineCalculation: 1(1)+6(1)=1+6=71(1) + 6(1) = 1 + 6 = 7.\newline7=77 = 7, so it satisfies the second equation.

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