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01(42x)e8x2x2dx\int _0^1\left(4-2x\right)e^{8x-2x^2}dx

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Q. 01(42x)e8x2x2dx\int _0^1\left(4-2x\right)e^{8x-2x^2}dx
  1. Define Integration by Parts: We need to integrate the function (42x)e(8x2x2)(4-2x)e^{(8x-2x^2)} with respect to xx from 00 to 11. This is not a standard integral, so we will use integration by parts, which states that udv=uvvdu\int u \, dv = uv - \int v \, du. We will let u=(42x)u = (4-2x) and dv=e(8x2x2)dxdv = e^{(8x-2x^2)} dx.
  2. Choose uu and dvdv: First, we need to find dudu by differentiating uu with respect to xx. Differentiating (42x)(4-2x) gives us du=2dxdu = -2 \, dx.
  3. Find dudu: Next, we need to find vv by integrating dvdv. We integrate e8x2x2e^{8x-2x^2} with respect to xx. This is not a straightforward integration, and it seems like we might have chosen the wrong uu and dvdv for integration by parts. Let's reconsider our choice for uu and dvdv.
  4. Find vv: Let's choose u=e8x2x2u = e^{8x-2x^2} and dv=(42x)dxdv = (4-2x) dx this time. This way, we can differentiate uu and hopefully get a simpler expression, and integrating dvdv should be straightforward.
  5. Apply Integration by Parts: We find dudu by differentiating uu with respect to xx. Differentiating e8x2x2e^{8x-2x^2} gives us du=(84x)e8x2x2dxdu = (8-4x)e^{8x-2x^2} dx.
  6. Reassess Strategy: Now, we integrate dvdv. Integrating (42x)dx(4-2x) dx is straightforward and gives us v=4xx2v = 4x - x^2.
  7. Reassess Strategy: Now, we integrate dvdv. Integrating (42x)dx(4-2x) dx is straightforward and gives us v=4xx2v = 4x - x^2.Now we apply the integration by parts formula: udv=uvvdu\int u dv = uv - \int v du. Substituting the values we have:\newline$\int(\(4\)\(-2\)x)e^{\(8\)x\(-2\)x^\(2\)} dx = (e^{\(8\)x\(-2\)x^\(2\)})(\(4\)x - x^\(2\)) - \int(\(4\)x - x^\(2\))(\(8\)\(-4\)x)e^{\(8\)x\(-2\)x^\(2\)} dx.
  8. Reassess Strategy: Now, we integrate \(dv\). Integrating \((4-2x) dx\) is straightforward and gives us \(v = 4x - x^2\).Now we apply the integration by parts formula: \(\int u dv = uv - \int v du\). Substituting the values we have:\(\newline\)\(\int(4-2x)e^{(8x-2x^2)} dx = (e^{(8x-2x^2)})(4x - x^2) - \int(4x - x^2)(8-4x)e^{(8x-2x^2)} dx\).We realize that the integral on the right side of the equation is more complicated than the original integral. This indicates that our choice for \(u\) and \(dv\) has not simplified the problem. We need to reassess our strategy for integrating this function.

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