Define Integration by Parts: We need to integrate the function (4−2x)e(8x−2x2) with respect to x from 0 to 1. This is not a standard integral, so we will use integration by parts, which states that ∫udv=uv−∫vdu. We will let u=(4−2x) and dv=e(8x−2x2)dx.
Choose u and dv: First, we need to find du by differentiating u with respect to x. Differentiating (4−2x) gives us du=−2dx.
Find du: Next, we need to find v by integrating dv. We integrate e8x−2x2 with respect to x. This is not a straightforward integration, and it seems like we might have chosen the wrong u and dv for integration by parts. Let's reconsider our choice for u and dv.
Find v: Let's choose u=e8x−2x2 and dv=(4−2x)dx this time. This way, we can differentiate u and hopefully get a simpler expression, and integrating dv should be straightforward.
Apply Integration by Parts: We find du by differentiating u with respect to x. Differentiating e8x−2x2 gives us du=(8−4x)e8x−2x2dx.
Reassess Strategy: Now, we integrate dv. Integrating (4−2x)dx is straightforward and gives us v=4x−x2.
Reassess Strategy: Now, we integrate dv. Integrating (4−2x)dx is straightforward and gives us v=4x−x2.Now we apply the integration by parts formula: ∫udv=uv−∫vdu. Substituting the values we have:$\int(\(4\)\(-2\)x)e^{\(8\)x\(-2\)x^\(2\)} dx = (e^{\(8\)x\(-2\)x^\(2\)})(\(4\)x - x^\(2\)) - \int(\(4\)x - x^\(2\))(\(8\)\(-4\)x)e^{\(8\)x\(-2\)x^\(2\)} dx.
Reassess Strategy: Now, we integrate \(dv\). Integrating \((4-2x) dx\) is straightforward and gives us \(v = 4x - x^2\).Now we apply the integration by parts formula: \(\int u dv = uv - \int v du\). Substituting the values we have:\(\newline\)\(\int(4-2x)e^{(8x-2x^2)} dx = (e^{(8x-2x^2)})(4x - x^2) - \int(4x - x^2)(8-4x)e^{(8x-2x^2)} dx\).We realize that the integral on the right side of the equation is more complicated than the original integral. This indicates that our choice for \(u\) and \(dv\) has not simplified the problem. We need to reassess our strategy for integrating this function.
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