{:[h(x)=17+(x)/(6)],[h(-18)=]:}

Substitute x with -18: Substitute x with -18 in the function h(x). We need to replace x with -18 in the function h(x) = 17 + x/6 to find the value of h(-18). h(-18) = 17 + (-18)/6Simplify the fraction: Simplify the fraction (-18)/6. Divide -18 by 6 to simplify the fraction. (-18)/6 = -3Add to 17: Add the result from Step 2 to 17. Now we add -3 to 17 to find the value of h(-18). h(-18) = 17 + (-3)Calculate final value: Calculate the final value. Adding 17 and -3 gives us the final value of h(-18). h(-18) = 14

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$\begin{array}{l}h(x)=17+\frac{x}{6} \\ h(-18)=\end{array}$

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Math Problems

Grade 6

Multiply using the distributive property

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\begin{array}{l}h(x)=17+\frac{x}{6} \\ h(-18)=\end{array}

Substitute $x$ with $-18$ : Substitute $x$ with $-18$ in the function $h(x)$ . We need to replace $x$ with $-18$ in the function $h(x) = 17 + \frac{x}{6}$ to find the value of $h(-18)$ . $h(-18) = 17 + \frac{(-18)}{6}$
Simplify the fraction: Simplify the fraction $(-18)/6$ . $\newline$ Divide $-18$ by $6$ to simplify the fraction. $\newline$ $(-18)/6 = -3$
Add to $17$ : Add the result from Step $2$ to $17$ . $\newline$ Now we add $-3$ to $17$ to find the value of $h(-18)$ . $\newline$ $h(-18) = 17 + (-3)$
Calculate final value: Calculate the final value. $\newline$ Adding $17$ and $-3$ gives us the final value of $h(-18)$ . $\newline$ $h(-18) = 14$