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{:[h(t)=4t+20],[h(◻)=4]:}

h(t)=4t+20h()=4 \begin{array}{l}h(t)=4 t+20 \\ h(\square)=4\end{array}

Full solution

Q. h(t)=4t+20h()=4 \begin{array}{l}h(t)=4 t+20 \\ h(\square)=4\end{array}
  1. Set h(t)h(t) equal to 44: To find the value of h()h(\square), we need to set the function h(t)h(t) equal to 44 and solve for the variable tt.
    h(t)=4t+20h(t) = 4t + 20
    h()=4h(\square) = 4
    So, we set 4t+204t + 20 equal to 44 and solve for tt.
    4411
  2. Subtract 2020 from both sides: Subtract 2020 from both sides of the equation to isolate the term with t.\newline4t+2020=4204t + 20 - 20 = 4 - 20\newline4t=164t = -16
  3. Divide both sides by 44: Divide both sides of the equation by 44 to solve for t.\newline4t4=164\frac{4t}{4} = \frac{-16}{4}\newlinet=4t = -4
  4. Value of t t for h()=4 h(\square) = 4 : Now that we have found the value of t t , we can say that h()=4 h(\square) = 4 corresponds to t=4 t = -4 .

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