{[h(1)=-5.3],[h(n)=h(n-1)*(-11)]:} Find an explicit formula for h(n). h(n)=

Given initial value: We are given the initial value h(1) = -5.3 and the recursive formula h(n) = h(n-1) * (-11). To find an explicit formula for h(n), we need to express h(n) in terms of n without the need for previous terms.Apply recursive formula: Let's start by applying the recursive formula to the first few terms to see if we can identify a pattern. h(1) = -5.3 h(2) = h(1) * (-11) = -5.3 * (-11) h(3) = h(2) * (-11) = (-5.3 * (-11)) * (-11) We can see that each term is the previous term multiplied by -11.Generalize the pattern: Now let's generalize this pattern. For h(n), we multiply the initial value -5.3 by -11, (n-1) times. h(n) = -5.3 * (-11)^(n-1) This is the explicit formula for h(n).

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{[h(1)=-5.3],[h(n)=h(n-1)*(-11)]:}
Find an explicit formula for
h(n).

h(n)=

$\begin{cases} h(1)=-5.3, h(n)=h(n-1)\cdot(-11) \end{cases}$ Find an explicit formula for $h(n)$ . $h(n)=$

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Algebra 1

Write variable expressions for geometric sequences

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\begin{cases} h(1)=-5.3, h(n)=h(n-1)\cdot(-11) \end{cases}

Find an explicit formula for

h(n)

h(n)=

Given initial value: We are given the initial value $h(1) = -5.3$ and the recursive formula $h(n) = h(n-1) \times (-11)$ . To find an explicit formula for $h(n)$ , we need to express $h(n)$ in terms of $n$ without the need for previous terms.
Apply recursive formula: Let's start by applying the recursive formula to the first few terms to see if we can identify a pattern. $\newline$ $h(1) = -5.3$ $\newline$ $h(2) = h(1) \times (-11) = -5.3 \times (-11)$ $\newline$ $h(3) = h(2) \times (-11) = (-5.3 \times (-11)) \times (-11)$ $\newline$ We can see that each term is the previous term multiplied by $-11$ .
Generalize the pattern: Now let's generalize this pattern. For $h(n)$ , we multiply the initial value $-5.3$ by $-11$ , $(n-1)$ times. $\newline$ $h(n) = -5.3 \times (-11)^{(n-1)}$ $\newline$ This is the explicit formula for $h(n)$ .