{:[{[h(1)=-12],[h(n)=h(n-1)*n]:}],[h(2)=]:}

Given: We are given the first term of the sequence: h(1) = -12 We are also given the recursive formula for the sequence: h(n) = h(n-1) * n We need to find the value of h(2).Recursive Formula: Using the recursive formula, we can find h(2) by substituting n with 2: h(2) = h(2-1) * 2 h(2) = h(1) * 2 We know that h(1) = -12, so we substitute that value in: h(2) = (-12) * 2Finding h(2): Now we perform the multiplication to find h(2): h(2) = (-12) * 2 h(2) = -24 This is the value of the second term in the sequence.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

{:[{[h(1)=-12],[h(n)=h(n-1)*n]:}],[h(2)=]:}

$\begin{array}{l}\left\{\begin{array}{l}h(1)=-12 \\ h(n)=h(n-1) \cdot n\end{array}\right. \\ h(2)=\end{array}$

View step-by-step help

Home

Math Problems

Algebra 1

Evaluate recursive formulas for sequences

Full solution

\begin{array}{l}\left\{\begin{array}{l}h(1)=-12 \\ h(n)=h(n-1) \cdot n\end{array}\right. \\ h(2)=\end{array}

Given: We are given the first term of the sequence: $\newline$ h( $1$ ) = $-12$ $\newline$ We are also given the recursive formula for the sequence: $\newline$ h( $n$ ) = h( $n-1$ ) $\times n$ $\newline$ We need to find the value of h( $2$ ).
Recursive Formula: Using the recursive formula, we can find $h(2)$ by substituting $n$ with $2$ :
$h(2) = h(2-1) \times 2$
$h(2) = h(1) \times 2$
We know that $h(1) = -12$ , so we substitute that value in:
$h(2) = (-12) \times 2$
Finding $h(2)$ : Now we perform the multiplication to find $h(2)$ : $\newline$ $h(2) = (-12) \times 2$ $\newline$ $h(2) = -24$ $\newline$ This is the value of the second term in the sequence.